我有一个数组$ final_arr ...给出下面的输出,然后我合并费用并创建一个新数组。
git status
我使用以下代码合并了它们:
git checkout test.c
这在我print_r($ final_arr)时给我下面的输出,因此现在费用总计,数组比以前小。
SELECT e.entity_id AS id,
v1.value AS name,
e.sku as sku,
d1.value AS version
FROM mguu_catalog_product_entity e
LEFT JOIN mguu_catalog_product_entity_varchar v1 ON (e.entity_id = v1.entity_id)
LEFT JOIN mguu_catalog_product_entity_varchar d1 ON (e.entity_id = d1.entity_id)
LEFT JOIN mguu_eav_attribute AS mea ON (v1.attribute_id = mea.attribute_id)
LEFT JOIN mguu_eav_entity_type AS meet ON (meet.entity_type_code = 'catalog_product')
WHERE v1.store_id = 0
AND mea.attribute_code = 'name'
AND mea.entity_type_id = meet.entity_type_id
AND d1.attribute_id = 171;
现在我想在子元素中像这样推送整个对象,但效果不佳。
Array
(
[0] => Array
(
[originator] =>Wayne
[niche] => Construction
[fee]=>30
)
[1] => Array
(
[originator] =>Josh
[niche] => Construction
[fee]=>30
)
[2] => Array
(
[originator] => Wayne
[niche] => Construction
[fee]=>50
)
[3] => Array
(
[originator] => Josh
[niche] => Construction
[fee]=>70
)
)
答案 0 :(得分:2)
您可以尝试像这样在foreach循环中获取下面子项中的所有值
foreach ($formEntries as $value) {
if (isset($final_arr[$value['originator']])) {
$final_arr[$value['originator']]['fee_potential'] = (!empty($final_arr[$value['originator']]['fee_potential']) ? $final_arr[$value['originator']]['fee_potential'] : 0) + (!empty($value['fee_potential']) ? $value['fee_potential'] : 0);
} else {
$final_arr[$value['originator']] = $value;
$data_orgin[] = $value['originator'];
}
$final_arr[$value['originator']]['sub'][] = $value; // new line for sub index
}
Demo。
答案 1 :(得分:1)
只需再添加一行,即可将$value
数组放入sub
数组
$final_arr = array();
foreach($formEntries as $value){
if(isset($final_arr[$value['originator']])){
$final_arr[$value['originator']]['fee_potential'] += $value['fee_potential'];
} else{
$final_arr[$value['originator']] = $value;
$data_orgin[] = $value['originator'];
}
// new line
$final_arr[$value['originator']]['sub'][] = $value;
}