我有一个简单的表,其中一列是同一表中另一个元素的PK,如下所示:
id | something | parent_id
___________|______________|____________
1 | colors | null
2 | red | 1
3 | green | 1
4 | blue | 1
... | ... | ...
我想获取所有具有条件的元素parent_id
的元素。
假设父元素应具有something='colors'
id | something | parent_id
___________|______________|____________
2 | red | 1
3 | green | 1
4 | blue | 1
环顾StackOverflow之后,我尝试了:
SELECT * FROM my_table WHERE
parent_id=(SELECT id FROM my_table WHERE something='colors')
还有:
SELECT * FROM my_table as t1 WHERE
t1.parent_id=(SELECT id FROM my_table as t2 WHERE t2.something='colors')
但我收到此错误:
错误:您的SQL语法有错误
原因是在我的文件之前被合并的先前文件中缺少;
。以上查询确实有效 ...
这不是我的领域,我知道一个“ 解决方案”(?)(项目中其他人使用的 )可能是:
SELECT * FROM my_table WHERE
parent_id=(SELECT id FROM (SELECT * FROM my_table) AS t1 WHERE something='colors')
但是我不是很喜欢
感谢任何人的帮助。
我知道我们应该LIMIT 1
或使用IN
来防止错误,我正尽最大努力简化sintax。
答案 0 :(得分:1)
使用存在
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答案 1 :(得分:1)
您可以:
SELECT t.*
FROM table t
WHERE EXISTS(SELECT 1 FROM table t1 WHERE t1.id = t.parent_id AND t1.something = 'colors');
答案 2 :(得分:1)
您可以通过简单的JOIN来获得它:
SELECT T1.* FROM my_table AS T1
JOIN my_table AS T2 ON T1.parent_id = T2.id
WHERE T2.something='colors';
此技术称为“自连接”。 Here了解更多详情。