Question

我需要找到每个区域中最大订购量的产品。结果应该是这样的：

| =IF(TEXT(TODAY(),"ddd")=IFERROR(VLOOKUP(A1, {{"M","Mon"};{"T","Tue"};{"W","Wed"};{"TH","Thu"};{"F","Fri"};{"S","Sat"};{"SU","Sun"}}, 2,0)),1) |

这是数据库：

P.S到数据库备份的链接： https://drive.google.com/open?id=15iE53xxni9C7uGaaa-kcK4b6WnmQv_1f

这是我尝试的代码，但它仅针对一个地区进行计算。我需要针对所有区域进行动态计算。

RegionID | ProductID

Answer 1

您可以使用该分区来实现此目的，我已根据您的图表加入了必要的表。

        SELECT REGIONID,PRODUCTID
        FROM(SELECT *,Row_number() over(partition by REGIONID order by Total desc) rn
        FROM(Select T.REGIONID,OD.PRODUCTID,COUNT(OD.PRODUCTID) as Total
        From Orders O
        LEFT JOIN EmployeeTerritories ET
        on O.EmployeeID=ET.EmployeeID
        LEFT JOIN Territories T
        on T.TerritoryID=ET.TerritoryID
        LEFT JOIN OrderDetails OD
        on OD.OrderID=O.OrderID
        GROUP BY T.REGIONID,OD.PRODUCTID)a)b
    WHERE b.rn=1

由于您想要一个不带分区的替代产品，因此可以有一个子查询，以`获得每个区域的最大产品销售量，并使用该子查询加入以获得每个区域的最大销售产品。

SELECT a.RegionID,a.PRODUCTID
(Select T.REGIONID,OD.PRODUCTID,COUNT(OD.PRODUCTID) as Total
    From Orders O
    LEFT JOIN EmployeeTerritories ET
    on O.EmployeeID=ET.EmployeeID
    LEFT JOIN Territories T
    on T.TerritoryID=ET.TerritoryID
    LEFT JOIN OrderDetails OD
    on OD.OrderID=O.OrderID
    GROUP BY T.REGIONID,OD.PRODUCTID)a
INNER JOIN
(Select RegionID,max(Total) as MaXTotal
FROM(Select T.REGIONID,OD.PRODUCTID,COUNT(OD.PRODUCTID) as Total
    From Orders O
    LEFT JOIN EmployeeTerritories ET
    on O.EmployeeID=ET.EmployeeID
    LEFT JOIN Territories T
    on T.TerritoryID=ET.TerritoryID
    LEFT JOIN OrderDetails OD
    on OD.OrderID=O.OrderID
    GROUP BY T.REGIONID,OD.PRODUCTID)b
GROUP BY RegionID)c
on c.RegionID=a.RegionID and a.Total=c.MaxTotal

Answer 2

join再次查询您的地区表。

select * 
from  Region
left join(
SELECT   T.RegionID, T.ProductID, MAX(T.Quantity) AS MaxOrders
FROM(
    SELECT Region.RegionID, [Order Details].ProductID, SUM([Order Details].Quantity) AS Quantity
    FROM Region
    JOIN Territories ON Region.RegionID = Territories.RegionID
    JOIN EmployeeTerritories ON Territories.TerritoryID = EmployeeTerritories.TerritoryID
    JOIN Employees ON EmployeeTerritories.EmployeeID = Employees.EmployeeID
    JOIN Orders ON Employees.EmployeeID = Orders.EmployeeID
    JOIN [Order Details] ON Orders.OrderID = [Order Details].OrderID
    GROUP BY Region.RegionID, [Order Details].ProductID
) T
--WHERE T.RegionID = 1
GROUP BY T.RegionID, T.ProductID
 ) A on A.RegionID =  Region.RegionID

Answer 3

交叉申请应该对此有所帮助。

conda list --version

Answer 4

您可以在聚合查询中使用窗口函数。看起来像：

SELECT RegionID, ProductID, Quantity AS MaxOrders
FROM (SELECT t.RegionID, od.ProductID, 
             SUM(od.Quantity) AS Quantity,
             ROW_NUMBER() OVER (PARTITION BY t.RegionID ORDER BY SUM(od.Quantity) DESC) as seqnum
      FROM Territories t JOIN
           EmployeeTerritories et
           ON t.TerritoryID = et.TerritoryID JOIN
           Employees e
           ON et.EmployeeID = e.EmployeeID JOIN
           Orders o
           ON e.EmployeeID = o.EmployeeID JOIN
           [Order Details] od
           ON o.OrderID = od.OrderID
      GROUP BY t.RegionID, od.ProductID
     ) t
WHERE seqnum = 1
ORDER BY MaxOrders DESC;

注意：

表别名使查询更易于编写和阅读。
Region表是不必要的，因为您需要的列在Territories中。
外部查询不需要聚合，只需过滤即可。

如何找到每个地区的最大订购量的产品？

4 个答案: