Question

嗯，我有一个复杂的问题。至少对我来说这很复杂。

所以我有一个数组，其中有一个数组，其中有一个数组。

并且我想根据最深数组中的属性过滤最顶层的数组。

让我说我有这个对象数组

var garages = [{
        "GarageId": 1,
        "GarageName": "Garage_001",
        "Sections": [{
            "SectionId": 1,
            "Name": "Section_002",
            "Cars": [{
                "Id": 5,
                "Model": "Bmw"
            }, {
                "Id": 6,
                "Model": "Mercedes"
            }]
        }, {
            "SectionId": 2,
            "Name": "Section_003",
            "Cars": [{
                "Id": 8,
                "Model": "Toyota"
            }, {
                "Id": 6,
                "Model": "Mercedes"
            }]
        }]

    },
    {
        "GarageId": 6,
        "GarageName": "Garage_006",
        "Sections": [{
            "Id": 1,
            "Name": "Section_007",
            "Cars": [{
                "Id": 5,
                "Model": "Bmw"
            }, {
                "Id": 6,
                "Model": "Mercedes"
            }]
        }, {
            "Id": 2,
            "Name": "Section_003",
            "Cars": [{
                "Id": 8,
                "Model": "Toyota"
            }, {
                "Id": 6,
                "Model": "Mercedes"
            }]
        }]

    }
]

例如，我想检索包含现代汽车的车库清单。我该怎么做？我已经尝试了几个小时，这就是我想出的。这可能是一段愚蠢的代码，但是我对处理这么多嵌套的数组感到困惑！

所以我的代码是这样的：

garages: any[] = [];
selectedCarModel: number: 8;

filterOnCarModel(carId) {
    this.garages = getGaragesFromServed();

    this.selectedCarModel = this.CarModels.find(c => c.Id == id);
    let filteredArray = this.garages
        .filter((garage) =>
            garage.Sections).
        filter((section) =>
            study.Cars.find((car) => car.Id == carId));
    this.garages = filteredArray;
}

感谢您的理解

Answer 1

var filteredGarages = garages.filter(garage => 
    garage.Sections.filter(section => 
         section.Cars.filter(car => car.Model.indexOf("Bmw")>=0)
   .length > 0)
.length > 0)

如何基于双嵌套数组中的属性过滤数组的元素

1 个答案: