Question

我已经在我的观点中做到了：

要序列化数据，我已经完成：

@login_required
@product_1_activation
def getcompanyObject(request, pk):
    company_details = get_object_or_404(company, pk=pk)
    all_objects = list(Company.objects.filter(pk=pk)) + list(Group1.objects.filter(Company=company_details.pk)) + list(Ledger1.objects.filter(Company=company_details.pk)) + list(Journal.objects.filter(Company=company_details.pk)) + 
    data = serializers.serialize('json', all_objects)
    data = json.dumps(json.loads(data), indent=4)
    response = HttpResponse(data , content_type='application/json')
    response['Content-Disposition'] = 'attachment; filename={}-{}.json'.format(company_details.Name,datetime.now()) 
    return response

然后我尝试：

from django.core.management import call_command

@login_required
def company_upload(request):
    if request.method == 'POST':
        new_company = request.FILES['myfile']

        obj_generator = serializers.json.Deserializer(new_company)

        for obj in obj_generator:
            call_command('loaddata', obj, verbosity=0)

    return render(request, 'company/import.html')

类似于python manage.py loaddata。

但是当我尝试执行此操作时，出现以下错误：

Problem installing fixture '<DeserializedObject: company': company(pk=87)> is not a known serialization format.

谁能告诉我为什么会这样？如果我的代码有任何错误，请帮助我纠正错误。

谢谢

Answer 1

您可能需要先将文件保存到磁盘。 loaddata命令期望参数为磁盘上fixture file的路径。

您可以将上传的文件保存到临时文件，然后在其上调用loaddata。

例如：

import tempfile
from django.core.management import call_command

@login_required
@product_1_activation
def company_upload(request):
    if request.method == 'POST':
        new_company = request.FILES['myfile']

        with tempfile.NamedTemporaryFile(dir='/tmp') as temp:
            for chunk in new_company.chunks():
                temp.write(chunk)
            call_command('loaddata', '/tmp/{}'.format(temp.name), verbosity=0)

    return render(request, 'company/import.html')

使用'loaddata'将数据加载到Django数据库中的问题

1 个答案: