如果我从不调用jasmine-ajax
方法,应该onreadystatechange
调用readyState
为4的send
吗?
如果上述不是预期的行为,如何使用jasmine-ajax
验证是否调用了send
方法?
这是正在测试的代码:
Loader = (function() {
var loadNames = function(url, success_callback, error_callback) {
var ajax = new XMLHttpRequest();
ajax.open("GET", url);
ajax.onreadystatechange = function () {
console.log("Ready state is " + ajax.readyState);
if (ajax.readyState === 4 && ajax.status === 200) {
success_callback(JSON.parse(ajax.responseText));
} else if (ajax.readyState === 4 && ajax.status !== 200) {
error_callback("There was a problem. Status returned was " + ajax.status);
}
};
ajax.onerror = function () {
error_callback("Unknown error");
};
// Shouldn't removing the call to send prevent
// onredystatechange from being called with readyState 4?
// ajax.send();
};
return {
loadNames: loadNames
};
})();
这是测试:
describe("Loader", function () {
var successFunction, failFunction;
beforeEach(function () {
jasmine.Ajax.install();
successFunction = jasmine.createSpy("successFunction");
failFunction = jasmine.createSpy("failFunction");
});
afterEach(function () {
jasmine.Ajax.uninstall();
});
describe("#loadNames", function () {
it("Makes a success callback with the data when successful", function () {
Loader.loadNames("someURL", successFunction, failFunction);
jasmine.Ajax.requests.mostRecent().respondWith({
"status": 200,
"contentType": 'application/json',
"responseText": '[1, 2, 4, 3, 5]'
});
// Shouldn't this fail since I never called send?
expect(successFunction).toHaveBeenCalledWith([1, 2, 4, 3, 5]);
});
});
});
我很惊讶地看到successFunction
被调用,因为被测代码从未调用过ajax.send()
。如果这是库的预期行为,那么如何spyOn
基础ajax
对象,以便可以验证测试中的代码调用了send
?
答案 0 :(得分:1)
是的,您没有调用ajax.send()
,但是由于这段代码而触发了ajax.onreadystatechange
事件:
jasmine.Ajax.requests.mostRecent().respondWith({
"status": 200,
"contentType": 'application/json',
"responseText": '[1, 2, 4, 3, 5]'
});
更改就绪状态并将就绪状态设置为完成。实际上,正如文档中也指出的那样:https://jasmine.github.io/2.6/ajax.html
关于如何检查xhr.send是否真正被调用的问题,此SO answer解释了您可以在beforeEach中执行以下操作来监视它:
spyOn(XMLHttpRequest.prototype, 'send');
取消注释加载程序中的xhr.send()部分后,您可以检查以下方法调用:
describe("#loadNames", function () {
it("Makes a success callback with the data when successful", function () {
Loader.loadNames("someURL", successFunction, failFunction);
jasmine.Ajax.requests.mostRecent().respondWith({
"status": 200,
"contentType": 'application/json',
"responseText": '[1, 2, 4, 3, 5]'
});
expect(XMLHttpRequest.prototype.open).toHaveBeenCalled();
});
});