Question

有一个表格，其中有“数量”，“插入日期”和“结果”列。

Quantity || TIMESTAMP || RESULT
Sample 1 || 2019-01-28 18:21:04 || PASS
Sample 2 || 2019-01-30 18:21:04 || FAIL

以此类推

单个查询如何仅给出零件总数，通过的数量和失败的GROUPED BY日期的数量？

Answer 1

如果您使用的是MySQL 5.x，则只能使用多个子查询。

select (select count(*) from Test ) as Total, passed.val, failed.val
from (select count(*) as val, tmstamp from Test where result = 'PASS' group by tmstamp) passed
   , (select count(*) as val, tmstamp from Test where result = 'FAIL' group by tmstamp) failed
WHERE passed.tmstamp = failed.tmstamp;

如果您使用的是MySQL8，则应研究CTE（公用表表达式）功能。

WITH Passed as (select count(*) as val, tmstamp from Test where result = 'PASS' group by tmstamp),
Failed as (select count(*) as val, tmstamp from Test where result = 'FAIL' group by tmstamp)
select (select count(*) from Test ) as Total, p.val, f.val
From Passed p
     join Failed f on f.tmstamp = p.tmstamp

如何在单个查询中获取零件总数，通过零件的数量和失败零件的数量

1 个答案: