我正在使用包含帐户对帐单的数组。我希望能够从数字值中删除逗号,以便能够在不损失生命值的情况下以逗号爆炸。
例如,我的数组包含如下索引:
26 => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1,316.01"
27 => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1,206.81"
我想删除“ 5,000”和其他货币值中的逗号,而不删除每个字符串之间的逗号,以便输出看起来像:
26 => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5000","","1316.01"
27 => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1206.81"
答案 0 :(得分:1)
您还可以将array_map与preg_replace_callback一起使用,并可以将其用作模式:
"\d{1,3}(?:,\d{3})+\.\d{2}"
"\d{1,3}
匹配"
,后接1-3位数字(?:,\d{3})!
重复1次以上以匹配逗号和3位数字\.\d{2}"
匹配一个点和一个2位数字,后跟"
在preg_replace_callback
的回调中,用一个空字符串替换逗号并返回匹配项。
例如:
$atm = array(
'26' => '20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1,316.01"',
'27' => '27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1,206.81"'
);
$atm = array_map(function($x) {
return preg_replace_callback('/"\d{1,3}(?:,\d{3})+\.\d{2}"/', function($m) {
return str_replace(',', '', $m[0]);
}, $x);
}, $atm);
print_r($atm);
结果:
Array
(
[26] => 20/08/2099,"ATM CASH WITHDRAWAL (ON-US) ATM CASH WITHDRAWAL (ON-US) EMPEMOM, LAGA ATM 2 LOGO NG 000360585490","",20/08/2018,"5,000","","1316.01"
[27] => 27/08/2027,BANK CHARGE 26 SMS CHARGE AND VAT FOR 27TH JUL - 23RD AUG 2018,2803064 028,27/08/2018,109.2,"","1206.81"
)
答案 1 :(得分:0)
您可以使用foreach数组并以逗号爆炸,然后替换为“,”每个数组,然后检查其是否为数字
foreach数组然后用逗号爆炸字符串
$stringArray=explode(",",$str)
然后在每个$ stringArray中替换“,”
$CheckNumber= str_replace(',', '', $string);
并通过以下方式检查是否为数字:
if (is_numeric($CheckNumber))
$stringArray[i]=$CheckNumber;
最后加入数组
join(",",$stringArray);