Question

我运行了这个查询：

select * From dbo.fn_split('Age,15,14,193,188 ',',')

它返回值，但在每个值前面切一个字符

我尝试在每个逗号之后添加空格

select * From dbo.fn_split('Age, 15, 14, 193, 188 ',',')

它奏效了。但我想知道为什么不使用逗号

select * From dbo.fn_split ('Age,15,14,193,188 ',',')

Answer 1

您没有发布问题所在的fn_split代码。但是，如果您的字符串长度少于8000个字符，则此功能将帮助您以最佳方式拆分它们。此功能是Eirikur Eirikson制造的Jeff Moden's splitter的修改版本。

CREATE FUNCTION [dbo].[DelimitedSplit8K_LEAD]
--===== Define I/O parameters
        (@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
 RETURN
--===== "Inline" CTE Driven "Tally Table” produces values from 0 up to 10,000...
     -- enough to cover VARCHAR(8000)
 WITH E1(N) AS (
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
                 SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
                ),                          --10E+1 or 10 rows
       E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
       E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
 cteTally(N) AS (--==== This provides the "zero base" and limits the number of rows right up front
                     -- for both a performance gain and prevention of accidental "overruns"
                 SELECT 0 UNION ALL
                 SELECT TOP (DATALENGTH(ISNULL(@pString,1))) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
                ),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
                 SELECT t.N+1
                   FROM cteTally t
                  WHERE (SUBSTRING(@pString,t.N,1) = @pDelimiter OR t.N = 0) 
                )
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
 SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY s.N1),
        Item = SUBSTRING(@pString,s.N1,ISNULL(NULLIF((LEAD(s.N1,1,1) OVER (ORDER BY s.N1) - 1),0)-s.N1,8000))
   FROM cteStart s
;
GO

Answer 2

ALTER FUNCTION [dbo]。[fn_Split]（@ text varchar（8000），@delimiter varchar（20）='，'）

返回@Strings表

（

位置int身份主键，

值varchar（8000）

）

AS

开始

DECLARE @index int

SET @index = -1

其中（LEN（@text）> 0）

开始

SET @index = CHARINDEX(@delimiter , @text) 

IF (@index = 0) AND (LEN(@text) > 0) 

  BEGIN  

    INSERT INTO @Strings VALUES (@text)

      BREAK 

  END 

IF (@index > 1) 

  BEGIN  

    INSERT INTO @Strings VALUES (LEFT(@text, @index - 1))  

    SET @text = RIGHT(@text, (LEN(@text) - @index)) 

  END 

ELSE

  SET @text = RIGHT(@text, (LEN(@text) - @index))

END

返回

END

Answer 3

我弄清楚我在做什么错。基本上，我在要分割的字符串末尾添加了一个额外的空间。如果您更改

Select * From dbo.fn_split(dbo.fn_split('Age,15,14,193,188 ',','))至Select * From dbo.fn_split('Age,15,14,193,188',',')。换句话说，摆脱数字188之后的多余空间，您将获得所需的结果。

Solution

dbo.fn_split函数在分割字符/分隔符之后切断下一个字符

3 个答案: