Question

小型WPF程序的源代码如下所示。它在c:\windows中的DataGrid下列出了目录。该名称是可以单击以在资源管理器中打开目录的链接。

（这只是一个概念证明程序，用于说明问题。）

是这样的：

我不仅要单击链接来运行打开操作，还希望对其进行设置，以便用户在突出显示一行时可以按o键来运行公开行动。

设置此内容的好方法是什么？请注意，该程序主要是在C＃中指定的，而不是XAML，因此，请尽可能在C＃中发布解决方案。但是，如有必要，也欢迎使用XAML答案！

MainWindow.xaml：

<Window x:Class="WpfFilesDataGrid.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:local="clr-namespace:WpfFilesDataGrid"
        mc:Ignorable="d"
        Title="MainWindow" Height="450" Width="800">
    <Grid>

    </Grid>
</Window>

MainWindow.xaml.cs：

using System.IO;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;

namespace WpfFilesDataGrid
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();

            var data_grid = new DataGrid()
            {
                IsReadOnly = true,
                AutoGenerateColumns = false,
                ItemsSource = new DirectoryInfo(@"c:\windows").GetDirectories()
            };

            {
                var setter = new EventSetter()
                {
                    Event = Hyperlink.ClickEvent,
                    Handler = (RoutedEventHandler)((sender, e) => 
                    {
                        System.Diagnostics.Process.Start((data_grid.SelectedItem as DirectoryInfo).FullName);
                    })
                };

                var style = new Style();

                style.Setters.Add(setter);

                var col = new DataGridHyperlinkColumn()
                {
                    Header = "FullName",
                    Binding = new Binding("FullName"),
                    ElementStyle = style
                };

                data_grid.Columns.Add(col);
            }

            data_grid.Columns.Add(new DataGridTextColumn()
            {
                Header = "CreationTime",
                Binding = new Binding("CreationTime")
            });

            var dock_panel = new DockPanel();

            dock_panel.Children.Add(data_grid);

            Content = dock_panel;
        }
    }
}

Answer 1

You could for example handle the PreviewKeyDown event:

data_grid.PreviewKeyDown += (s, e) =>
{
    if(e.Key == Key.O && data_grid.SelectedItem is DirectoryInfo di)
        System.Diagnostics.Process.Start(di.FullName);
};

DataGrid-在当前项目上运行事件处理程序的键

1 个答案: