Question

我试图显示两个选定球队之间获胜和平局的比赛百分比，但是我发现很难区分这两个球队。

Connection con = DBConnector.connect();
             ResultSet rs = con.createStatement().executeQuery("SELECT DISTINCT t1.title AS title1, t2.title AS title2, g.score1, g.score2, g.winner AS winner, g.team1_id AS team1,  g.home AS home FROM games g INNER JOIN teams AS t1 ON g.team1_id = t1.id INNER JOIN teams AS t2 ON g.team2_id = t2.id WHERE (t1.title = '"+team1 +"' AND t2.title = '" +team2+ "') OR (t1.title = '"+team2 +"' AND t2.title = '" +team1+ "');");
            while(rs.next()){

                if(rs.getString("team1").equals(rs.getString("home"))){
                if(rs.getInt("winner") == 1){
                        teamOneWin++;
                    }else{
                        teamTwoWin++;
                    }

                }else if(rs.getInt("winner") == 2){
                    if(rs.getString("team1").equals(rs.getString("home"))){
                        teamOneWin++;
                    }else{
                        teamTwoWin++;
                    }

                }else if(rs.getInt("winner") == 0){
                    if(rs.getString("team1").equals(rs.getString("home"))){
                    draw++;
                    }


            }

我正在检查查询中的team1值是否等于查询中的主队值。如果它们相等，并且组1是列获胜者的值，我希望teamOneWin增加。我指定获胜者1，获胜者2和获胜者0（比赛是平局）。我指定这些是因为我有一个赢家3值，该值也没有玩。

我知道的下面一行是有缺陷的，因为team1始终等于主队，但是我需要一种方法来区分任一支球队，并根据获胜者的价值增加正确的一支。

if(rs.getString("team1").equals(rs.getString("home"))){

在SQL中使用COUNT会更好吗？

这是我的游戏表的表结构：

CREATE TABLE "games" (
    "team1_id"  integer NOT NULL,
    "team2_id"  integer NOT NULL,
    "home"  integer,
    "score1"    varchar DEFAULT null,
    "score2"    varchar DEFAULT null,
    "winner"    integer,
    "created_at"    DATETIME DEFAULT CURRENT_TIMESTAMP,
    PRIMARY KEY("team1_id","created_at"),
    FOREIGN KEY("team1_id") REFERENCES "teams"("id"),
    FOREIGN KEY("team2_id") REFERENCES "teams"("id")
);

这是我的餐桌团队的餐桌结构：

CREATE TABLE "teams" (
    "id"    integer NOT NULL PRIMARY KEY AUTOINCREMENT,
    "title" varchar NOT NULL,
    "code"  varchar,
    "synonyms"  varchar,
    "address"   varchar,
    "web"   varchar,
    "created_at"    DATETIME DEFAULT CURRENT_TIMESTAMP
);

非常感谢。

Answer 1

据我了解，在winner表的games列中，您存储了一个整数值，指示：

0: draw
1 or 2: either team won
3: game not played

如果是这种情况，那么我认为您可以获取所需的结果，而无需从数据库中获取数据并遍历每一行。
尝试以下查询：

select 
  t.title1, t.title2,
  100.0 * t.draws / (t.draws + t.wins) percentdraws,
  100.0 * t.wins / (t.draws + t.wins) percentwins
from (
  select 
    'team1' title1, 'team2' title2,
    sum(case when g.winner = 0 then 1 else 0 end) draws,
    sum(case when g.winner <> 0 then 1 else 0 end) wins
  from games g 
  inner join teams t1 on t1.id = g.team1_id 
  inner join teams t2 on t2.id = g.team2_id
  where 
    ((t1.title = 'team1' and t2.title = 'team2') or (t2.title = 'team1' and t1.title = 'team2'))
    and 
    g.winner < 3
) t

将'team1'和'team2'更改为所选团队的名称。

试图区分两个2个Java变量

1 个答案: