Question

我试图弄清楚如何计算一个数组中一个特定元素相互出现的次数。就像掷骰子时，数字6出现了多少次。

例如：：如果这是抛出56611166626634416的结果，那么结果将是2倍！！

我已经尝试过使用for循环并比较元素，但是它会继续计数是否 6 彼此相邻出现两次以上。

package dice;
import java.util.Scanner;
public class dice2 {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        int k=0;
         Scanner input1 =new Scanner(System.in);
          Scanner input2 =new Scanner(System.in);
          System.out.println("please enter the number of throws!"); 
          int N=input1.nextInt();
          int count=0;
          String faces[]=new String[N];
          System.out.println("enter the faces of the dice !");
         while((N>=1) && (N<= 100) && (N!=count))
         {
            String x=input2.next();
             switch(x) {

             case "1":
                 faces[count]=x;
                 break;

             case "2":
                 faces[count]=x;
                 break;
             case "3":
                 faces[count]=x;
                 break;
             case "4":
                 faces[count]=x;
                 break;
             case "5":
                 faces[count]=x;
                 break;
             case "6":
                 faces[count]=x;
                 break;

                 default : System.out.println(" enter 1-6");
             }
             count++;    
         }

         for(int i=0;i<faces.length;i++) {
              for(int j=i+1;j<faces.length;j++) {     
                  if((faces[i].equals("6")) && (faces[j].equals("6")) )
                  { 
                      k++; i=j; 
                  }
                  else 
                      break;
              }
         System.out.println("k is "+k);
    }
}

Answer 1

以下是仅打印连续出现的数字的工作代码：

public class dice
{
    public static void main(String[] args)
    {
        String input = "11555677666551189988777"; //suppose you saved input using Scanner.Next() in 'input'
        char[] number = new char[input.length()];  // will hold each distintive number
        int[] occurence = new int[input.length()]; //will hold the occurence of that number
        int j=0, distinct = 0, visited = -1;

        for (int i = 0; i < input.length() - 1; i++) 
        { 
        // Counting occurrences of input[i] 
            while (input.charAt(i) == input.charAt(i + 1)) 
            {
                if(i!=0)
                {   
                    if (input.charAt(i) != input.charAt(i - 1))
                    {
                        number[j] = input.charAt(i);
                        distinct++;
                        j++;
                    }
                }
                else    
                {
                    number[j] = input.charAt(i);
                    distinct++;
                    j++;
                }
                i++; 
                if(i + 1 == input.length()) 
                    break; 

            } 

        }

        for(int i = 0; i < distinct; i++)
        {  
            int count = 1;  
            for(j = i+1; j < distinct; j++)
            {  
                if(number[i] == number[j])
                {  
                    count++;  
                    //To avoid counting same element again  
                    occurence[j] = visited;  
                }  
            }  
            if(occurence[i] != visited)  
                occurence[i] = count;  
        }  


        System.out.println("----------------------------------------------");  
        System.out.println("         Element    |   Consecutive Occurence");  
        System.out.println("----------------------------------------------");  
        for(int i = 0; i < distinct; i++)
        {  
            if(occurence[i] != visited)  
                System.out.println("                " + number[i] + "   |   " + occurence[i]);  
        }  
        System.out.printf("\nAll other numbers doesn't Occured Consecutively !!"); 
    }
}

输出：

----------------------------------------------
         Element    |   Consecutive Occurence
----------------------------------------------
             6      |      3
             1      |      1
             4      |      1

All other numbers doesn't Occurred Consecutively !!!

希望这就是您想要的，请告诉我是否需要与此相关的其他事情。

如何知道同一元素在数组中出现了多少次？

1 个答案: