Question

我有一个大型数据集，需要用两种不同的方式进行分组。我希望我能够运行一次查询，这样就不必运行两个单独的查询。

我想可以使用ROLLUP或GROUPING SETS来做到这一点，但我必须承认我不完全了解如何将它们用于此目的。

这是我要执行的操作的基本示例。我想用一个查询回答的两个问题是：

每个公司每天创建多少个用户？
在整个期间，哪些公司创造了最多的用户？前5家公司就足够了。

CREATE TABLE IF NOT EXISTS tmp_users (
    id INTEGER NOT NULL,
    name TEXT NOT NULL,
    created TIMESTAMP NOT NULL,
    companyid INTEGER NOT NULL
);

INSERT INTO tmp_users (id, name, created, companyid)
VALUES 
(1, 'Lindsay', '2019-01-01', 1),
(2, 'Michael', '2019-01-02', 1),
(3, 'Stan', '2019-01-04', 3),
(4, 'Gob', '2019-01-04', 1),
(5, 'Buster', '2019-01-01', 1),
(6, 'Lucille', '2019-01-03', 2),
(7, 'Sally', '2019-01-05', 3);

-- Get users created per day, per company
SELECT
    DATE_TRUNC('DAY', created) AS created,
    companyid,
    COUNT(*) AS numberofusers
FROM tmp_users
GROUP BY 
    DATE_TRUNC('DAY', created),
    companyid
ORDER BY DATE_TRUNC('DAY', created) DESC;

-- Users per company, with filter
SELECT
    companyid,
    COUNT(*) AS numberofusers
FROM tmp_users
GROUP BY 
    companyid
HAVING COUNT(*) > 1
ORDER BY COUNT(*) DESC;

Answer 1

grouping sets可用于在一次选择中返回多个聚合级别：

-- Get users created per day, per company
SELECT *
FROM
 (
   SELECT
      DATE_TRUNC('DAY', created) AS created,
      companyid,
      Count(*) AS numberofusers,
      Row_Number() -- instead of TOP n
      Over (PARTITION BY CASE WHEN DATE_TRUNC('DAY', created) IS NULL THEN 0 ELSE 1 END 
            ORDER BY Count(*) DESC) AS rn
   FROM tmp_users
   GROUP BY GROUPING SETS
    (
     (DATE_TRUNC('DAY', created), companyid)  -- daily data
     ,companyid                               -- company data
    )
 ) AS dt
WHERE created IS NOT NULL  -- all daily data
   OR rn <= 5              -- plus the TOP 5 companies
ORDER BY created ASC NULLS FIRST;

请参见db<>fiddle

在PostgreSQL中以两种方式对数据集进行分组

1 个答案: