在Android中(Java或Kotlin都可以),如何从经度和纬度获取城市名称?
下面,我编写了一个显示地址数据的功能。我想对其进行修改,以使其返回城市名称:
private fun getCity(context: Context, latitude: Float, longitude: Float) {
val gcd = Geocoder(context, Locale.getDefault())
val addresses = gcd.getFromLocation(latitude.toDouble(), longitude.toDouble(), 1)
Log.d("-----", "-----")
Log.d("latitude", latitude.toString())
Log.d("longitude", longitude.toString())
if (addresses.size > 0) {
val locality = addresses[0].locality
if (locality != null) {
Log.d("locality", locality.toString())
}
val adminArea = addresses[0].adminArea
if (adminArea != null) {
Log.d("adminArea", adminArea.toString())
}
val subAdminArea = addresses[0].subAdminArea
if (subAdminArea != null) {
Log.d("subAdminArea", subAdminArea.toString())
}
val subLocality = addresses[0].subLocality
if (subLocality != null) {
Log.d("subLocality", subLocality.toString())
}
val thoroughfare = addresses[0].thoroughfare
if (thoroughfare != null) {
Log.d("thoroughfare", thoroughfare.toString())
}
val subThoroughfare = addresses[0].subThoroughfare
if (subThoroughfare != null) {
Log.d("subThoroughfare", subThoroughfare.toString())
}
val extras = addresses[0].extras
if (extras != null) {
Log.d("extras", extras.toString())
}
val premises = addresses[0].premises
if (premises != null) {
Log.d("premises", premises.toString())
}
val postalCode = addresses[0].postalCode
if (postalCode != null) {
Log.d("postalCode", postalCode.toString())
}
val featureName = addresses[0].featureName
if (featureName != null) {
Log.d("featureName", featureName.toString())
}
val getAddressLine0 = addresses[0].getAddressLine(0)
if (getAddressLine0 != null)
Log.d("getAddressLine0", getAddressLine0.toString())
for (i in 0 until addresses[0].maxAddressLineIndex) {
Log.d("getAddressLine($i)", addresses[0].getAddressLine(i).toString())
}
}
}
如果我运行getCity(context, 53.7f, -1.506f)
,则featureName
包含正确的城市名称Wakefield。
如果我运行getCity(context, 53.801f, -1.549f)
,则featureName
现在包含街道名称Portland Place。 getAddressLine(0)
返回英国利兹LS1 3DA,卡尔弗利街5号的波特兰广场,其中包含正确的利兹城市。我可以从getAddressLine(0)中删除街道名称,邮政编码和门牌号码,然后再留给城市。不幸的是,在某些极端情况下无法使用,因为有时街道名称在getAddressLine(0)
中包含缩写,而在thoroughfare
中则不包含缩写。
这个问题How to Get City Name by Latitude &Longitude in android?的答案完全不同,因为不同国家/地区的地址以不同的方式存储。
为了获得英国2个相邻城市的城市名称,我似乎需要编码很多变化和边缘情况。我如何从全球任何经度或纬度中获取正确的城市名称?世界上有太多城市要测试我的代码并为其测试代码,甚至可能有很多我不知道的边缘情况和变化。
修改
以下功能可以正确获取英国的城市。不幸的是,它在美国和印度以及任何有州的国家中都失败了。
private fun getCity(context: Context, latitude: Float, longitude: Float): String {
val gcd = Geocoder(context, Locale.getDefault())
val addresses = gcd.getFromLocation(latitude.toDouble(), longitude.toDouble(), 1)
if (addresses.size > 0) {
val locality = addresses[0].locality
val getAddressLine0 = addresses[0].getAddressLine(0)
if (getAddressLine0 != null) {
val strs = getAddressLine0.split(",").toTypedArray()
if (strs.count() == 1) {
if (locality != null && locality != "") {
return "$locality, ${strs[0]}"
}
return strs[0]
}
for (str in strs) {
var tempStr = str.replace(postalCode, "")
if (tempStr != str) {
tempStr = tempStr.trim()
if (locality != null && locality != "" && locality != tempStr) {
return "$locality, $tempStr"
}
return tempStr
}
}
}
if (locality != null) {
return locality
}
}
return ""
}
答案 0 :(得分:0)
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List addresses = geocoder.getFromLocation(MyLat, MyLong, 1);
String cityName = addresses.get(0).getAddressLine(0);
String stateName = addresses.get(0).getAddressLine(1);
String countryName = addresses.get(0).getAddressLine(2);
答案 1 :(得分:0)
private void getPlaceInfo(double lat,double lon)引发IOException {
mGeocoder = new Geocoder(AddressSelectorActivity.this, Locale.ENGLISH);
List<Address> addresses = mGeocoder.getFromLocation(lat, lon, 1);
if (addresses.get(0).getPostalCode() != null) {
String ZIP = addresses.get(0).getPostalCode();
Log.d("ZIP CODE",ZIP);
google_add_pincode.setText(ZIP);
}
if (addresses.get(0).getLocality() != null) {
String city = addresses.get(0).getLocality();
Log.d("CITY",city);
}
if (addresses.get(0).getAdminArea() != null) {
String state = addresses.get(0).getAdminArea();
Log.d("STATE",state);
}
if (addresses.get(0).getCountryName() != null) {
String country = addresses.get(0).getCountryName();
Log.d("COUNTRY",country);
}
}