我正在尝试创建azure存储表,并使用c#将记录插入其中。 我已经成功创建了该表,但是在向其中插入记录时却给了400 Bad Request存储异常。
检入调试器后:
StorageException.RequestInformation.ExtendedErrorInformation.ErrorMessage
它显示OutOfRangeInput错误
“其中一个请求输入超出范围。\ nRequestId:862fdbae-6002-000c-1e7c-ef9373000000 \ n时间:2019-04-10T09:06:05.9840359Z”
我帮助了这个线程Azure table storage returns 400 Bad Request
和
它仍然给我同样的错误。 这是我的代码:
public void GetGPSFileData(Config objConfig, TraceWriter log)
{
try
{
BindData objData = new BindData();
string date = DateTime.Now.Date.ToString("ddMMyyyy");
string storageTable = "TABLE" + date + objData.REPCODE;
TableStorage tableStorage = new TableStorage(objData);
CreateTableStorage(objConfig, storageTable, tableStorage, log);
}
catch (StorageException ex)
{
log.Info($"Storage Exception while reading GPS File Data from Azure Storage: " + ex.RequestInformation.ExtendedErrorInformation.ErrorMessage + DateTime.Now);
throw ex;
}
catch (Exception ex)
{
log.Info($"Error while reading GPS File Data from Azure Storage: " + ex.Message + DateTime.Now);
throw ex;
}
}
TableStorage.cs
public class TableStorage: TableEntity
{
public string CLIENTID { get; set; }
public string REPCODE { get; set; }
public int ENTRYNO { get; set; }
public string DEVICEID { get; set; }
public double LAT { get; set; }
public double LNG { get; set; }
public DateTime DATE_TIME { get; set; }
public string PCODE { get; set; }
public string PNAME { get; set; }
public DateTime TXNDATE { get; set; }
public TableStorage(BindData objData)
{
PartitionKey = objData.CLIENTID;
RowKey = ToAzureKeyString(Guid.NewGuid().ToString());
Timestamp = DateTimeOffset.Now;
CLIENTID = objData.CLIENTID;
REPCODE = objData.REPCODE;
ENTRYNO = objData.ENTRYNO;
DEVICEID = objData.DEVICEID;
LAT = objData.LAT;
LNG = objData.LNG;
DATE_TIME = objData.DATE_TIME;
PCODE = objData.PCODE;
PNAME = objData.PNAME;
TXNDATE = objData.TXNDATE;
}
public string ToAzureKeyString(string str)
{
var sb = new StringBuilder();
foreach (var c in str
.Where(c => c != '/'
&& c != '\\'
&& c != '#'
&& c != '/'
&& c != '?'
&& !char.IsControl(c)))
sb.Append(c);
return sb.ToString();
}
}
创建并插入存储表代码:
public void CreateTableStorage(Config objConfig, string tableName, TableStorage tableStorage, TraceWriter log)
{
try
{
CloudStorageAccount storageAccount = CloudStorageAccount.Parse(objConfig.TABLE_STORAGE_CONN_STRING);
CloudTableClient tableClient = storageAccount.CreateCloudTableClient();
CloudTable table = tableClient.GetTableReference(tableName);
table.CreateIfNotExists();
TableOperation insert = TableOperation.Insert(tableStorage);
table.Execute(insert);
}
catch(StorageException ex)
{
log.Info($"Storage Exception while inserting record into Table Storage: " + ex.RequestInformation.ExtendedErrorInformation.ErrorMessage + DateTime.Now);
throw ex;
}
catch(Exception ex)
{
log.Info($"Error while inserting record into Table Storage: " + ex.Message + DateTime.Now);
throw ex;
}
}
可能是什么问题?我是全新的天蓝色储物桌。 请帮忙。 预先感谢。
答案 0 :(得分:4)
我相信您的类继承TableEntity时可能缺少默认/无参数的构造函数。从TableStorage接收到该对象时,非常需要无参数的构造函数来反序列化该对象。
请参考this answer。
可能的更正代码:
public class TableStorage: TableEntity
{
public string CLIENTID { get; set; }
public string REPCODE { get; set; }
public int ENTRYNO { get; set; }
public string DEVICEID { get; set; }
public double LAT { get; set; }
public double LNG { get; set; }
public DateTime DATE_TIME { get; set; }
public string PCODE { get; set; }
public string PNAME { get; set; }
public DateTime TXNDATE { get; set; }
public TableStorage(){}//Added default constructor
public TableStorage(BindData objData)
{
PartitionKey = objData.CLIENTID;
RowKey = ToAzureKeyString(Guid.NewGuid().ToString());
Timestamp = DateTimeOffset.Now;
CLIENTID = objData.CLIENTID;
REPCODE = objData.REPCODE;
ENTRYNO = objData.ENTRYNO;
DEVICEID = objData.DEVICEID;
LAT = objData.LAT;
LNG = objData.LNG;
DATE_TIME = objData.DATE_TIME;
PCODE = objData.PCODE;
PNAME = objData.PNAME;
TXNDATE = objData.TXNDATE;
}
public string ToAzureKeyString(string str)
{
var sb = new StringBuilder();
foreach (var c in str
.Where(c => c != '/'
&& c != '\\'
&& c != '#'
&& c != '/'
&& c != '?'
&& !char.IsControl(c)))
sb.Append(c);
return sb.ToString();
}
}
答案 1 :(得分:4)
由于TXNDATE
属性的值而出现问题。如果您查看共享的图片,则发送的值为1/1/01
(即DateTime.MinValue
),而允许的最小值为1/1/1601
。
一旦您为TXNDATE
传递了正确的值,就不会看到此错误。