Question

我正在尝试制作一张包含30张卡的纸牌，一次取出一张，然后使用pop将它们分成两个玩家，但我不知道为什么pop不起作用，为什么我的pop不起作用

我尝试使用.remove，但我的老师说必须使用pop，但我不知道为什么pop不起作用

card_deck = [["yellow",1],["yellow",2],["yellow",3],["yellow",4],    ["yellow",5],["yellow",6],["yellow",7],["yellow",8],["yellow",9],     ["yellow",10],
["red",1],["red",2],["red",3],["red",4],["red",5],["red",6],["red",7],    ["red",8],["red",9],["red",10],
["black",1],["black",2],["black",3],["black",4],["black",5],["black",6],    ["black",7],["black",8],["black",9],["black",10]]

cardies = 30

while True:
  if cardies > 0:
    u1_card = random.choice(card_deck)
    u2_card = random.choice(card_deck)
    print ("player 1's card is", u1_card)
    print("player 2's card is", u2_card)
    card_deck.pop(u1_card)
    card_deck.pop(u2_card)
    len(card_deck) - 1
  if u1_card == u2_card:
    card_deck.pop

我希望纸牌（card_deck）被随机洗牌，然后一次将一张纸牌分配给每个玩家（u1_card，u2_card），直到没有纸牌为止左。

Answer 1

您要调用该函数，因此必须使用方括号。应该是：

card = card_deck.pop() # for your last line of code

此外，pop()需要一个索引参数，因此card_deck.pop(u1_card)将不起作用。您可以使用.index()来获取索引，

card_deck.pop(card_deck.index(u1_card))

另外，我认为您的意思是用以下行更新cardies：len(card_deck) - 1

cardies -= 1 # you might have to change this to 2, to get the desired result because you are popping 2 cards per loop iteration

您还应该有一个条件来结束while循环，否则当列表为空时会遇到错误，例如：

while len(card_deck) != 0:
    ...

如何在2D数组上使用pop？

1 个答案: