Question

我有以下三个字符串：

inputs = [
    "Season 12",
    "Season 1a",
    "Season 1-2"
]

我正在尝试只匹配第一个。这是我当前使用的正则表达式：

outputs = []
for input in inputs:
    output = re.search(r'(Staffel|Season|Saison|S\.?)?\s?(\d{0,})(?!(-|[a-z][A-Z]))', input, re.IGNORECASE).group(2)
    outputs.append(output)

assert(outputs == ['12','',''])
# AssertionError, values were ['12', '1', '']

当前，此方法适用于Season 12，Season 1-2，但不适用于Season 1a（不应返回任何内容）。

Answer 1

import re
inputs = [
    "Season 12",
    "Season 1a",
    "Season 1-2",
    "Seinfeld, Season 1 (UHD)"
]
re_num = re.compile(
    r'(Staffel|Season|Saison|S\.?)\s?((\d+)$|(\d+)\s)',
    flags=re.IGNORECASE
)

for s in inputs:
    m = re_num.search(s)
    if m:
        print(s, '-->', m.group(2))

结果：

Season 12 --> 12
Seinfeld, Season 1 (UHD) --> 1

Answer 2

不确定Seinfeld, Season 1 (UHD)想要什么。在这里捕获了它，但是如果您不想要它，请将最后一部分从(?:\s|$)更改为简单的$

import re

inputs = [
    "Season 12",
    "Season 1a",
    "Season 1-3",
    "Seinfeld, Season 1 (UHD)",
    "Seinfeld, Season 1"
]

outputs = []
for input in inputs:
    output = re.search(r'(?:Staffel|Season|Saison|S\.?)?\s(\d+)(?:\s|$)', input, re.IGNORECASE)
    if (output != None):
        outputs.append(output.group(1))
    else:
        outputs.append('')

print(outputs)
assert(outputs == ['12','','','1','1'])

输出：

['12', '', '', '1', '1']

正则表达式匹配没有后缀的数字

2 个答案: