我正在寻找一种基于python的方式来解密安全pdf。
对我来说，无法使用module FiniteStateMachine(output reg [2:0] Count, input clock, reset);
reg[2:0] state, next_state;
parameter S0 = 3'b000, S1 = 3'b001, S2 = 3'b010, S3 = 3'b011, S4 = 3'b100, S5 = 3'b101, S6 = 3'b110, S7 = 3'b111;
always @ (posedge clock, negedge reset)
if(reset==0) state<=S0;
else state <= next_state;
always @ (state)
case(state)
S0: begin
Count = S0;
next_state = S1;
end
S1: begin
Count = S1;
next_state = S2;
end
S2: begin
Count = S3;
next_state = S3;
end
S3: begin
Count = S7;
next_state = S4:
end
S4: begin
Count = S6;
next_state = S5;
end
S5: begin
Count = S4;
next_state = S0;
end
endcase
endmodule
之类的需要安装的库。
否则，任何提示都提示我如何开始编写自己用python解密的方法？
不再支持当前方式：
qpdf Python：3.5.2
操作系统：Linux