如何在循环的表组件中显示“ empName”和此JSON的其他详细信息?
我正在使用第三方API,当我将loyeeID发送到API URL时,该API提供了一个嵌套的JSON对象。
订阅后,我将响应存储在变量“ AllPostedJobs”中
{
"status": "All Jobs",
"result": [
{
"_id": "5c90fd3cfc7f3b0017803319",
"job_title": "Web Designer",
"job_desc": "test description ...",
"location": "Mangalore",
"experiance": "Freshers",
"job_type": "Full-Time",
"salary_package": "3L",
"job_keywords": "Photoshop, Illustrator",
"email_id": "hr@shreemithra.com",
"employerID": "5c7e99c2a7a9eb00174de2b2",
"company_name": "Shreemithra Designs",
"AppliedStudentDetails": [
{
"_id": "5c9393c1a918d60017de7e55",
"empName": "Anup",
"empID": "5c939375a918d60017de7e53",
"job_title": "Web Designer"
}
],
"__v": 1
},
{
"_id": "5c913570cb78a100177ab23a",
"job_title": "Full Stack Developer",
"job_desc": "htjhsv dhsd jh jds fjshgdfkhsdmhfd;lw eiwiwemsd. This is a sample job description.",
"location": "Pune",
"experiance": "2 Years",
"job_type": "Part-Time",
"salary_package": "8L - 10L PA",
"job_keywords": "Angular, Node JS, React, HTML5. CSS3",
"email_id": "info@shreemithra.com",
"employerID": "5c7e99c2a7a9eb00174de2b2",
"company_name": "Shreemithra Designs",
"AppliedStudentDetails": [
{
"_id": "5c9393c9a918d60017de7e56",
"empName": "Anup",
"empID": "5c939375a918d60017de7e53",
"job_title": "Full Stack Developer"
},
{
"_id": "5ca60fa5ba17730017182ca8",
"empName": "Amit Pateriya",
"empID": "5c7795acfd39640017ca4c37",
"job_title": "Full Stack Developer"
}
],
"__v": 2
}
]
}
答案 0 :(得分:0)
您可以通过将HTML模板中的控件绑定到组件的属性来绑定显示数据。
显示组件属性的最简单方法是通过插值绑定属性名称。通过插值,您可以将属性名称放在视图模板中,并用双花括号括起来:{{AllPostedJobs.status}}
。
<div id="result-container" *ngFor="let record of AllPostedJobs.result">
<another-component [record]= "record"></another-component>
</div>
或者根据您的需要,您可以将整个结果数据移交给另一个组件。
现在,您的另一个组件应该已定义@Input
来处理传入的数据:
export class AnotherComponent {
@Input() record: Array<any>;
在另一个组件模板中:
<div *ngFor="let student of record?.AppliedStudentDetails">
<span>{{student.empName}}</span>
<span [innerText]="student.job_title"></span>
</div>
答案 1 :(得分:0)
最简单的方法是,当您从api接收数据然后将其发送到 函数,然后应用多次循环通过添加键来更改数据 数据的开头以及该值的例子
var data = [{"id":1, "name":"smith","applicant":{"roll": 32,"class":10}}];
data[0].applicantRoll = data[0].applicant.roll;
data[0].applicantClass = data[0].applicant.class;
现在您可以轻松申请* ng了,试试看。