在这种情况下，我在mysql数据库中将新的休假插入“ leave”表中：
+--------+---------+---------+-------------+----------+--------------------------
|ID_LEAVE|ID_WORKER| FNAME | LNAME | BEGIN_DATE | END_DATE |
+--------+---------+---------+---------+-------------+--------------------+------
| 5 | 10 | MARIO | NEED |2019-03-22 07:00:00 |2019-03-25 15:00:00 |
+--------+---------+---------+-------------+----------+--------------------------
当我在下面总结mysql查询中的离开时间时：
SELECT leave.ID_LEAVE,
leave.ID_WORKER,
leave.BEGIN_DATE,
leave.END_DATE,
time_format(SUM((datediff(leave.END_DATE, leave.BEGIN_DATE) + 1) * (time(leave.END_DATE) - time(leave.BEGIN_DATE))), '%H:%i:%s') AS 'LEAVE TIME'
FROM leave
GROUP BY leave.ID_LEAVE
我得到了请假时间= 32:00:00
但是我也看到它也算周末（星期六和星期日）。我不知道如果没有周末我应该怎么改变呢。在这种情况下，请假时间应为16:00:00。有人可以请问我可以更改哪种查询。谢谢您的光临。 ：）
答案 0 :(得分：2)
您可以通过日历表（based on this solution）使用以下解决方案：
SELECT ID_LEAVE, SEC_TO_TIME(SUM(TIME_TO_SEC(TIMEDIFF(TIME(end_date), TIME(begin_date)))))
FROM (
SELECT ADDDATE('1970-01-01', t4 * 10000 + t3 * 1000 + t2 * 100 + t1 * 10 + t0) AS date_value
FROM
(SELECT 0 t0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t0,
(SELECT 0 t1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t1,
(SELECT 0 t2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t2,
(SELECT 0 t3 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t3,
(SELECT 0 t4 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) t4
) calendar INNER JOIN `leave` ON calendar.date_value BETWEEN DATE(leave.BEGIN_DATE) AND DATE(leave.END_DATE)
WHERE NOT WEEKDAY(date_value) IN (5, 6)
GROUP BY ID_LEAVE
答案 1 :(得分：0)
这个@ Prochu1991非常具有挑战性，但我想我可以为您构建一个查询。
编辑：以下查询在某些情况下存在一些问题。因此，我不建议您使用它，但请留在此处，以防您可以做一些事情：
-- Query 6: Final calculation add SUM of total leave time GROUP BY ID_LEAVE,ID_WORKER.
SELECT ID_LEAVE,ID_WORKER,BEGIN_DATE,END_DATE,
SEC_TO_TIME(SUM(TIME_TO_SEC(leave_TIME))) AS 'LEAVE TIME'
FROM (
Query 5: Calculating leave time on each date only if VALID_LEAVE_DATES=1.
SELECT ID_LEAVE,ID_WORKER,BEGIN_DATE,END_DATE,
IF(VALID_LEAVE_DATES=1,SEC_TO_TIME(TIME_TO_SEC(TIME(end_date))-TIME_TO_SEC(TIME(begin_date))),0) AS 'LEAVE_TIME'
FROM (
-- Query 4: Add checking' if any of the dates are in the weekend, it will be set as 0.
SELECT leave_dates,
IF(DAYNAME(LEAVE_DATES) IN ('Saturday','Sunday'),0,1) AS 'VALID_LEAVE_DATES',
ID_LEAVE,ID_WORKER,BEGIN_DATE,END_DATE FROM (
-- Query 3: In this part, the main reason is to create dates between BEGIN_DATE and END_DATE.
SELECT ID_LEAVE,ID_WORKER,BEGIN_DATE,END_DATE,
-- concatenating extracted year-month with days generated from Query 1.
CONCAT_WS('-',DATE_FORMAT(BEGIN_DATE, '%Y-%m'),LPAD(days,2,0)) AS 'LEAVE_DATES' FROM
-- Query 1: This part is creating day value directly from query. If you run this individually, you'll get a day value from 0 to 39.
(SELECT 1 AS 'id'
a+b AS 'days' FROM
(SELECT 0 a UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) a,
(SELECT 0 b UNION SELECT 10 UNION SELECT 20 UNION SELECT 30) dd
-- Query 1 end here.
) ee
LEFT JOIN
-- Query 2: This is your original query. I removed the SUM in select.
(SELECT 1 AS 'id',
leave.ID_LEAVE,
leave.ID_WORKER,
leave.BEGIN_DATE,
leave.END_DATE
FROM leave GROUP BY leave.ID_LEAVE) cd
-- Query 2 end here.
ON ee.id=cd.id
WHERE days BETWEEN DAY(BEGIN_DATE) AND DAY(END_DATE) -- `WHERE` condition only take date value between BEGIN_DATE and END_DATE from Query 2.
ORDER BY LEAVE_DATES) LCALC -- Query 3 end here.
) vvv GROUP BY ID_LEAVE,LEAVE_DATES -- Query 4 end here.
) tuv -- Query 5 end here.
GROUP BY ID_LEAVE,ID_WORKER; -- Query 6 end here.
希望您能理解我的解释。我将继续使用该查询，看看是否有一种方法可以减少某些过程（减少查询）。
编辑2： 好的，我一直在进行@ Prochu1991：
SELECT *,IF(valid_leave_days=0, TIMEDIFF(end_date,begin_date),
-- Assuming that normal working hours is '08:00:00'. If more, you just need to change here.
SEC_TO_TIME(TIME_TO_SEC('08:00:00')*Valid_leave_days)) AS 'Total_leave_time'
-- So I convert 8 hours to seconds multiply with valid_leave_days calculated and convert it back to time. I think you understand this part.
FROM
(SELECT *,
-- This part where the CASE start is actually just determining how many leave days per person.
-- Then minus with the total of weekend per week (sat & sun = 2 days).
CASE
WHEN datedif<6 THEN datedif --if leave days are less than 6 days, it return datedif.
WHEN datedif=6 THEN datedif-1 --if leave days=6, datedif-1 day > because in any day you start you will surely get one weekend.
WHEN datedif BETWEEN 7 AND 12 THEN datedif-2 --if leave days between 7 and 12, datedif-2.
WHEN datedif=13 THEN datedif-3 -- from here you should get the idea.
WHEN datedif BETWEEN 14 AND 19 THEN datedif-4
WHEN datedif=20 THEN datedif-5
WHEN datedif BETWEEN 21 AND 26 THEN datedif-6
WHEN datedif=27 THEN datedif-7
WHEN datedif BETWEEN 28 AND 34 THEN datedif-8
-- Note that this is only up to 34 days. if you want to add more days, just make sure the calculation is correct.
END AS 'Valid_leave_days'
FROM
(SELECT *,DATEDIFF(end_date,begin_date) AS 'datedif' FROM LEAVE) a) b;
答案 2 :(得分：0)
对不起，我发布了另一个答案。你可以试试这个吗？这是对上面第二个查询的修改，其中包含了begin_date的检查：
SELECT *,TIMEDIFF(end_date,begin_date),IF(valid_leave_days2=0, TIMEDIFF(end_date,begin_date),SEC_TO_TIME(TIME_TO_SEC('08:00:00')*Valid_leave_days2)) AS 'Total_leave_time' FROM
(SELECT *,DAYNAME(begin_date),
CASE
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF=6 THEN datedif-1
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF > 6 AND datedif < 13 THEN datedif-2
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF=13 THEN datedif-3
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF > 13 AND datedif < 20 THEN datedif-4
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF=20 THEN datedif-5
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF > 20 AND datedif < 27 THEN datedif-6
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF=27 THEN datedif-7
WHEN DAYNAME(begin_date)='Monday' AND DATEDIF > 27 AND datedif < 34 THEN datedif-8
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF=5 THEN datedif-1
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF > 5 AND datedif < 12 THEN datedif-2
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF=12 THEN datedif-3
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF > 12 AND datedif < 19 THEN datedif-4
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF=19 THEN datedif-5
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF > 19 AND datedif < 26 THEN datedif-6
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF=26 THEN datedif-7
WHEN DAYNAME(begin_date)='Tuesday' AND DATEDIF > 26 AND datedif < 33 THEN datedif-8
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF=4 THEN datedif-1
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF > 4 AND datedif < 11 THEN datedif-2
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF=11 THEN datedif-3
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF > 11 AND datedif < 18 THEN datedif-4
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF=18 THEN datedif-5
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF > 18 AND datedif < 25 THEN datedif-6
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF=25 THEN datedif-7
WHEN DAYNAME(begin_date)='Wednesday' AND DATEDIF > 25 AND datedif < 32 THEN datedif-8
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF=3 THEN datedif-1
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF > 3 AND datedif < 10 THEN datedif-2
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF=10 THEN datedif-3
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF > 10 AND datedif < 17 THEN datedif-4
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF=17 THEN datedif-5
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF > 17 AND datedif < 24 THEN datedif-6
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF=24 THEN datedif-7
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF > 24 AND datedif < 31 THEN datedif-8
WHEN DAYNAME(begin_date)='Thursday' AND DATEDIF=31 THEN datedif-9
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF=3 THEN datedif-1
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF > 3 AND datedif < 9 THEN datedif-2
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF=9 THEN datedif-3
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF > 9 AND datedif < 16 THEN datedif-4
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF=16 THEN datedif-5
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF > 16 AND datedif < 23 THEN datedif-6
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF=23 THEN datedif-7
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF > 23 AND datedif < 30 THEN datedif-8
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF=30 THEN datedif-9
WHEN DAYNAME(begin_date)='Friday' AND DATEDIF > 30 AND datedif < 37 THEN datedif-10
ELSE datedif END AS 'valid_leave_days2' FROM
(SELECT *,DATEDIFF(end_date,begin_date-INTERVAL 1 DAY) AS 'datedif' FROM LEAVE) a) b;
对于您的评论“但我不知道为什么：万一算是万一，在2019-03-20 07:00:00-2019-03-21 15:00:00的情况下，它是08:00:00 16:00:00”，我发现DATEDIFF不在计算中包括BEGIN_DATE或END_DATE。可以说，在您的情况下，如果您进行DATEDIFF(END_DATE,BEGIN_DATE)，则它会像这样END_DATE-BEGIN_DATE进行计数，因此21 / 03-20 / 03只能得到1天！哦，天哪，我也想通了。我已经检查过MySQL是否具有类似DATE_COUNT这样的功能，但是没有。因此，我对添加DATEDIFF(end_date,begin_date-INTERVAL 1 DAY) AS 'datedif'的底部查询做了一些修改。因此，- INTERVAL 1 DAY使函数开始从BEGIN_DATE开始计算天数。
P / S：您也可以像这样DATEDIFF(end_date + INTERVAL 1 DAY,begin_date) AS 'datedif'。
编辑：这些是通过运行上述查询获得的测试数据的结果。
+------------+-------------+-----------------------+-----------------------+-----------+-----------------------+---------------------+---------------------------------+--------------------+
| "ID_LEAVE" | "ID_WORKER" | "BEGIN_DATE" | "END_DATE" | "datedif" | "DAYNAME(begin_date)" | "valid_leave_days2" | "TIMEDIFF(end_date,begin_date)" | "Total_leave_time" |
+------------+-------------+-----------------------+-----------------------+-----------+-----------------------+---------------------+---------------------------------+--------------------+
| "3" | "26" | "2019-03-20 07:00:00" | "2019-04-01 15:00:00" | "13" | "Wednesday" | "9" | "296:00:00" | "72:00:00" |
| "4" | "22" | "2019-03-20 07:00:00" | "2019-03-20 15:00:00" | "1" | "Wednesday" | "1" | "08:00:00" | "08:00:00" |
| "5" | "27" | "2019-03-01 07:00:00" | "2019-03-31 15:00:00" | "31" | "Friday" | "21" | "728:00:00" | "168:00:00" |
| "6" | "28" | "2019-03-22 07:00:00" | "2019-03-31 15:00:00" | "10" | "Friday" | "6" | "224:00:00" | "48:00:00" |
| "7" | "29" | "2019-03-20 07:00:00" | "2019-03-21 15:00:00" | "2" | "Wednesday" | "2" | "32:00:00" | "16:00:00" |
| "8" | "30" | "2019-03-20 07:00:00" | "2019-03-22 15:00:00" | "3" | "Wednesday" | "3" | "56:00:00" | "24:00:00" |
| "9" | "31" | "2019-03-28 07:00:00" | "2019-04-01 15:00:00" | "5" | "Thursday" | "3" | "104:00:00" | "24:00:00" |
+------------+-------------+-----------------------+-----------------------+-----------+-----------------------+---------------------+---------------------------------+--------------------+