Question

因此，我必须使用密码对控制台应用程序进行加密，我做了一些有效的操作，但是有一个问题，后退键不会擦除输入的字符，它也被算作字符，我该怎么做呢？做它的工作，以消除角色？

这是代码：

void main()
{
    char password[20], my_password[20] = "password";
    int i;
    char ch;
    system("cls");
    cout << "PASSWORD: ";


    i = 0;
    do
    {
        ch = _getch();
        password[i] = ch;
        if (ch != 27 && ch != 13 && ch != 9)
            cout<<"*";
        else
            break;
        i++;
    } while (i < 19);
    password[i] = '\0';



    if (strcmp(password, my_password) != 0) 
    {
        cout << "\n\nIncorrect password !!!";
        cin.get();
        return;
    }
    cout << "\n\nPassword is correct !";
    cout <<"\n\nThe program is executed !";
    cin.get();
}

Answer 1

“我该如何做才能消除角色？”

使用Owner库。像ncurses。

Answer 2

您可以检查接收到的字符是否为退格键，减量i是否可以有效删除最后一个字符。

    i = 0;
    do
    {
        ch = _getch(); // get the character
        if(ch == DEL || ch == BS) // check for backspace
        {
            i--;
            cout << BS;
        }
        else if(ch >= ' ' && ch <= '~') // check if its valid ASCII
        {
            password[i] = ch;
            cout << "*";
            i++;
        }
        else if (ch == 27 || ch == 13 || ch == 9) // check if entry is complete
        {
            break;
        }


    } while (i < 19);

    password[i] = '\0';

其他地方

#define BS '\b'
#define DEL 127

Answer 3

void main()
{
    char password[20], my_password[20] = "password";
    int i;
    char ch;
    system("cls");
    cout << "PASSWORD: ";


    i = 0;
    do
    {
        ch = _getch();
        if (ch == 8)
        {
            i--;
            cout << "\b \b";
            continue;
        }

        password[i] = ch;
        if (ch != 27 && ch != 13 && ch != 9)
            cout << "*";
        else
            break;
        i++;
    } while (i < 19);
    password[i] = '\0';



    if (strcmp(password, my_password) != 0)
    {
        cout << "\n\nIncorrect password !!!";
        cin.get();
        return;
    }
    cout << "\n\nPassword is correct !";
    cout << "\n\nThe program is executed !";
    cin.get();
}

不是最干净的代码，但是它可以工作。减少计数器以覆盖前一个字符，并输出两个由空格分隔的退格字符。

如何使退格键不算作字符？

3 个答案: