我有一个功能如下的LEFT JOIN MySQL查询:
SELECT
COUNT(HTG_ScheduleRequest.ID) AS current_job,
HTG_TechProps.EmpNumber,
HTG_TechProps.EmpFirstName,
HTG_TechProps.EmpLastName,
HTG_TechProps.Veh_Number
FROM HTG_TechProps
LEFT JOIN HTG_ScheduleRequest ON HTG_TechProps.EmpNumber = HTG_ScheduleRequest.SSR
AND (HTG_ScheduleRequest.ScheduleDateCurrent = CURDATE() || HTG_ScheduleRequest.ScheduleDateExact = CURDATE())
AND RecordType = '1'
AND HTG_ScheduleRequest.JobStatus IN (2,5,8,3,4,7)
GROUP BY HTG_TechProps.EmpNumber ORDER BY HTG_TechProps.EmpNumber ASC
我需要像这样在初始SELECT表中添加一些条件:
HTG_TechProps.EmpStatus='A'
当我在LEFT JOIN之前添加WHERE语句,并且在LEFT JOIN之后添加这样的AND时,会出现语法错误。它将被忽略,仍然返回不等于A的记录。
LEFT JOIN HTG_ScheduleRequest ON HTG_TechProps.EmpNumber = HTG_ScheduleRequest.SSR
AND HTG_TechProps.EmpStatus='A'
答案 0 :(得分:2)
LEFT JOIN
中第一个表的条件应该放在WHERE
子句中:
SELECT COUNT(sr.ID) AS current_job,
tp.EmpNumber, tp.EmpFirstName, tp.EmpLastName, tp.Veh_Number
FROM HTG_TechProps tp LEFT JOIN
HTG_ScheduleRequest sr
ON tp.EmpNumber = sr.SSR AND
(sr.ScheduleDateCurrent = CURDATE() OR sr.ScheduleDateExact = CURDATE()
) AND
sr.RecordType = '1' AND -- assume this comes from SR
sr.JobStatus IN (2, 5, 8, 3, 4, 7)
WHERE tp.EmpStatus='A'
GROUP BY tp.EmpNumber -- this is okay assuming that it is unique or (equivalently) a primary key
ORDER BY tp.EmpNumber ASC;
请注意,这引入了表别名,因此查询更易于编写和阅读。
答案 1 :(得分:0)
您应该使用OR
SELECT
COUNT(HTG_ScheduleRequest.ID) AS current_job,
HTG_TechProps.EmpNumber,
HTG_TechProps.EmpFirstName,
HTG_TechProps.EmpLastName,
HTG_TechProps.Veh_Number
FROM HTG_TechProps
LEFT JOIN HTG_ScheduleRequest ON HTG_TechProps.EmpNumber = HTG_ScheduleRequest.SSR
AND (HTG_ScheduleRequest.ScheduleDateCurrent = CURDATE() OR HTG_ScheduleRequest.ScheduleDateExact = CURDATE())
AND RecordType = '1'
AND HTG_ScheduleRequest.JobStatus IN (2,5,8,3,4,7)
GROUP BY HTG_TechProps.EmpNumber
ORDER BY HTG_TechProps.EmpNumber ASC
,如果您想在主表列的位置应用条件,则可以在以下位置使用:
SELECT
COUNT(HTG_ScheduleRequest.ID) AS current_job,
HTG_TechProps.EmpNumber,
HTG_TechProps.EmpFirstName,
HTG_TechProps.EmpLastName,
HTG_TechProps.Veh_Number
FROM HTG_TechProps
LEFT JOIN HTG_ScheduleRequest ON HTG_TechProps.EmpNumber = HTG_ScheduleRequest.SSR
AND HTG_ScheduleRequest.JobStatus IN (2,5,8,3,4,7)
WHERE (HTG_ScheduleRequest.ScheduleDateCurrent = CURDATE() OR HTG_ScheduleRequest.ScheduleDateExact = CURDATE())
AND HTG_TechProps.RecordType = '1'
GROUP BY HTG_TechProps.EmpNumber
ORDER BY HTG_TechProps.EmpNumber ASC