Question

我有一个像这样的表

________________________________________________________
|  ID   | ADDRESS_LINE1 | CITY   | STATE | ZIP  | TYPE |
________________________________________________________
| 12345 | abcd st       | city1  |   CA  | zip1 |   1  |
| 12345 | abcd st       | city1  |   CA  | zip1 |   2  |
| 12345 | efgh st       | city2  |   CA  | zip2 |   3  |
________________________________________________________

在此表中，我需要检查Type是1还是3而不是2。

我需要类似的输出：

对于指定的表记录

_______________________________________________________________
|  ID   | RESIDENTIAL_ADDRESS      | MAILING_ADDRESS          |
_______________________________________________________________
| 12345 | abcd st, city1, CA, zip1 | efgh st, city2, CA ,zip2 |
_______________________________________________________________

如果表中没有类型1

_______________________________________________________________
|  ID   | RESIDENTIAL_ADDRESS      | MAILING_ADDRESS          |
_______________________________________________________________
| 12345 |                          | efgh st, city2, CA ,zip2 |
_______________________________________________________________

如果表中没有类型3

_______________________________________________________________
|  ID   | RESIDENTIAL_ADDRESS      | MAILING_ADDRESS          |
_______________________________________________________________
| 12345 | abcd st, city1, CA, zip1 |                          |
_______________________________________________________________

如果类型1和类型3都不存在

_______________________________________________________________
|  ID   | RESIDENTIAL_ADDRESS      | MAILING_ADDRESS          |
_______________________________________________________________
| 12345 |                          |                          |
_______________________________________________________________

我在尝试什么：

SELECT DISTINCT ID, 
    ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP (CASE WHEN TYPE = 1 THEN 1 ELSE 0 END) AS RESIDENTIAL_ADDRESS, 
    ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP (CASE WHEN TYPE = 3 THEN 1 ELSE 0 END) AS MAILING_ADDRESS 
FROM TABLE
WHERE ID =  12345;

这会引发错误

ORA-00904：ZIP：无效的标识符

我知道我想念一些东西。请帮助构建查询。

Answer 1

ZIP列与其余代码之间缺少分隔符

如果案例内容是其他列，则需要为逗号分隔的RESIDENTIAL_ADDRESS和MAILING_ADDRESS列ZIP

  SELECT DISTINCT ID, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP, (CASE WHEN TYPE = 1 THEN 1 ELSE 0 END) AS RESIDENTIAL_ADDRESS, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP,  (CASE WHEN TYPE = 3 THEN 1 ELSE 0 END) AS MAILING_ADDRESS 
  FROM TABLE
  WHERE ID =  12345;

如果案例内容是要连接的其他列，则||您需要用逗号分隔RESIDENTIAL_ADDRESS和MAILING_ADDRESS的单独列ZIP

  SELECT DISTINCT ID, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP || (CASE WHEN TYPE = 1 THEN 1 ELSE 0 END) AS RESIDENTIAL_ADDRESS, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP ||  (CASE WHEN TYPE = 3 THEN 1 ELSE 0 END) AS MAILING_ADDRESS 
  FROM TABLE
  WHERE ID =  12345;

或

  SELECT DISTINCT ID, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP || ',' || (CASE WHEN TYPE = 1 THEN 1 ELSE 0 END) AS RESIDENTIAL_ADDRESS, 
      ADDRLINE1 || ',' || CITY || ',' || STATE || ',' || ZIP || ',' || (CASE WHEN TYPE = 3 THEN 1 ELSE 0 END) AS MAILING_ADDRESS 
  FROM TABLE
  WHERE ID =  12345;

如果在同一行上需要两个不同的行，则需要在表上为每个地址两次联接，例如：

   SELECT DISTINCT a.ID, 
    a.ADDRLINE1 || ',' || a.CITY || ',' || a.STATE || ',' || a.ZIP AS RESIDENTIAL_ADDRESS, 
    b.ADDRLINE1 || ',' || b.CITY || ',' || b.STATE || ',' || b.ZIP  AS MAILING_ADDRESS 
FROM TABLE a 
INNER JOIN TABLE b ON a.ID = b.ID 
  AND a.TYPE = 1 
  AND b.TYPE = 3 
WHERE a.ID =  12345;

仅针对Oracle中特定记录类型的条件语句

1 个答案: