Question

这是我的样品表

CREATE TABLE agentskills 
( 
    id          INT PRIMARY KEY NOT NULL IDENTITY, 
    skilluserid INT, 
    skillid     INT NOT NULL, 
    skilltypeid INT, 
    priority    INT DEFAULT 0 
)

这些是我的示例数据

INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (1,21,1,1)
INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (1,22,1,1)

INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (2,23,1,1)
INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (2,24,1,1)

INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (3,21,1,1)
INSERT INTO AGENTSKILLS (skilluserid , skillid, SKILLTYPEID,priority ) VALUES (3,22,1,1)

此处，“ skilluserid”是具有技能“ skillid”的用户的ID。

我如何获取具有技术技能组合的用户/ skilluserid？

例如：获取具有技能21和22或22和21或21,22,23的用户。具有21和22的任意组合。

Answer 1

您可以使用聚合和having：

select skilluserid
from agentskills
where skillid in (21, 22)
group by skilluserid
having count(distinct skillid) = 2;  -- "2" = size of list in where clause

Answer 2

如果需要选择所有列，则可以使用exist

select t1.* from agentskills t1
where  exists ( select 1 from agentskills t2 where t1.skilluserid=t2.skilluserid
                 and skillid in (21, 22) 
                 having count(distinct skillid) = 2
            ) and skillid in (21, 22)

Answer 3

您可以使用相交，

select skilluserid
from agentskills 
where skillid =21

INTERSECT

select skilluserid
from agentskills 
where skillid =22

获取具有列组合的记录

3 个答案: