Question

通过添加新命令从第一个Discord机器人构建。创建第二个命令时，即使代码位于不同的标题下，我也会在代码中先前收到错误“功能已定义”。

@client.command()
async def on_message(message):
    if message.author == client.user:
        return

    if message.content.startswith('!hello'):
        msg = 'Hello {0.author.mention}'.format(message)
        await client.send_message(message.channel, msg)

My first command above, worked fine.

@client.command()
async def on_message(message):
    if message.author == client.user:
        return

    if message.content.startswith('!roll'):
        msg = 'So, {0.author.mention} you rolled for a {}'.format(random.randint(1,20))
        await client.send_message(message.channel, msg)

第二个错误，即先前在第10行（在第一个函数中）已经定义了异步操作

Answer 1

通过使用def来定义一个函数。一个函数必须是唯一的，并且不能用相同的名称定义两次。

解决方案可以

@client.command()
async def on_message(message):
    if message.author == client.user:
        return

    if message.content.startswith('!hello'):
        msg = 'Hello {0.author.mention}'.format(message)
        await client.send_message(message.channel, msg)
    elif message.content.startswith('!roll'):
        msg = 'So, {0.author.mention} you rolled for a {}'.format(random.randint(1,20))
        await client.send_message(message.channel, msg)

Discord bot上的函数已定义的错误

1 个答案: