Question

我正在尝试编写一个程序来匹配文件中的正则表达式。我文件的初始行如下所示

Alternate Take with Liz Copeland (Day 1) (12am-1am)                    
    Saturday  March 31, 2007                    
        No.    Artist    Song    Album (Label)    Comment
    buy    1    Tones on Tail    Go! (club mix)    Everything! (Beggars Banquet)    
    buy    2    Devo    (I Can't Get No) Satisfaction    Anthology: Pioneers Who Got Scalped (Warner Archives/Rhino)

我匹配文件第一行的代码如下

with open("data.csv") as my_file:
  for line in my_file:
      re_show = re.compile(r'(Alternate Take with Liz Copeland) \((.*?)\)\s\((.*?)\)')
      num_showtitle_lines_matched = 0
      m_show = re.match(re_show, line)
      bool(m_show) == 1
      if m_show:
         num_showtitle_lines_matched += 1

         show_title =  m_show.group()

print("Num show lines matched --> {}".format(num_showtitle_lines_matched))
print(show_title)

它应该给我以下结果

Alternate Take with Liz Copeland (Day 1) (12am-1am)
num_showtitle_lines_matched -->1

但是我的结果没有显示任何输出。请让我知道如何完成此操作。谢谢。

Answer 1

如评论中所示：只需将num_showtitle_lines_matched = 0放在循环上方：

with open("data.csv") as my_file:
  num_showtitle_lines_matched = 0
  for line in my_file:
      re_show = re.compile(r'(Alternate Take with Liz Copeland) \((.*?)\)\s\((.*?)\)')      
      m_show = re.match(re_show, line)     
      bool(m_show) == 1
      if m_show:
         num_showtitle_lines_matched += 1
         show_title =  m_show.group()
print("Num show lines matched --> {}".format(num_showtitle_lines_matched))
print(show_title)

输出：

Num show lines matched --> 1
Alternate Take with Liz Copeland (Day 1) (12am-1am)

无法从python中的每一行搜索和编译正则表达式代码

1 个答案: