我在postgres中有一个树结构,我想获取每个可见节点的嵌套节点数,该节点数除了隐藏子项及其后代之外的所有子项。您可以看一下SQL查询来了解一下。 我正在尝试在Django 1.11.20中实现以下查询:
select
id,
path,
(
select count(*)
from tree_node
where
path <@ t.path and
not path <@ array(
select path
from tree_node
where path <@ t.path and visibility_id = 0
)
) as nested_nodes
from tree_node t;
我正在尝试:
TreeQuerySet.py
...
def annotate_visibile_nested_nodes_count(self):
"""
Get all nested nodes for current path except the hidden ones and their descendants
"""
from src.tree.models import Visibility
invisible_nested_nodes_paths = self.model.objects.filter(path__descendantsof=OuterRef(OuterRef('path')))\
.filter(visibility_id=Visibility.HIDE)\
.values('path')
visible_nested_nodes_count = self.model.objects.filter(path__descendantsof=OuterRef('path'))\
.exclude(path__descendantsin=Subquery(invisible_nested_nodes_paths))\
.annotate(count=Count('*'))\
.values('count')[:1]
return self.annotate(
nested_nodes=Subquery(visible_nested_nodes_count, output_field=IntegerField())
)
我收到来自Django
的错误消息:
File ".../django/db/models/expressions.py", line 237, in output_field
raise FieldError("Cannot resolve expression type, unknown output_field")
FieldError: Cannot resolve expression type, unknown output_field
我无法弄清楚错误是来自第一个注释还是第二个注释以及如何解决。我将嵌套Subquery
用作最里面的选择,引用最外面的path
列。自定义查找仅适用于Postgres的<@
运算符。
预先感谢您的帮助。