Question

我有以下3张桌子：

用户：[id，名称，管理员...]
事件：[id，user_id，类型...]
消息：[id，user_id，...]

我想构造一个执行以下操作的查询：

->从表 users 中选择尚未计划 type “ collection”

的 event 的所有用户

->并且具有少于3种类型的 “ collection_reminder”

消息

->谁不是 admin

我设法弄清楚了该查询的第一部分，但是当我尝试添加3表，进行计数等操作时，一切都变得有点像梨花了。

Answer 1

这是一个可能完成任务的查询。每个需求在WHERE子句中表示为条件，并在需要时使用相关子查询：

SELECT u.*
FROM users u
WHERE 
    NOT EXISTS (
        SELECT 1 
        FROM events e 
        WHERE e.user_id = u.id AND e.type = 'collection'
    )
    AND (
        SELECT COUNT(*) 
        FROM messages m 
        WHERE m.userid = u.id AND m.type = 'collection_reminder'
    ) <= 3
    AND u.admin IS NULL

Answer 2

我将在头顶尝试此操作，以期出现一些合奏问题，但想法如下。

您可以使用左联接过滤掉没有活动计划的人。在左侧的联接中，查询第二部分的元素将显示为null。

theString

现在，我不认为这是性能最高的方法，而是一种搜索包含3条以下消息的人的简单方法：

select * from users u
left join events e on e.user_id = u.id
where e.user_id is null

然后过滤不是管理员的人是最简单的：D

select * from users u
left join events e on e.user_id = u.id
where u.id in (
   select COUNT(*) from messages m where m.user_id = u.id HAVING COUNT(*)>3;
)
and e.user_id is null

希望有帮助。

Answer 3

这几乎是您的要求的直接翻译，按照您列出要求的顺序：

SELECT u.*
FROM users AS u
WHERE u.user_id NOT IN (SELECT user_id FROM events WHERE event_type = 'Collection')
   AND u.user_id IN (
      SELECT user_id 
      FROM messages 
      WHERE msg_type = 'Collection Reminder' 
      GROUP BY user_id 
      HAVING COUNT(*) < 3
   )
   AND u.admin = 0

或者，这可以完全通过联接来完成：

SELECT u.*
FROM users AS u
LEFT JOIN events AS e ON u.user_id = e.user_id AND e.event_type = 'Collection'
LEFT JOIN messages AS m ON u.user_id = m.user_id AND m.msg_type = 'Collection Reminder'
WHERE u.admin = 0
   AND e.event_id IS NULL        -- No event of type collection
GROUP BY u.user_id -- Note: you should group on all selected fields, and 
                   -- some configuration of MySQL will require you do so.
HAVING COUNT(DISTINCT m.message_id) < 3   -- Less than 3 collection reminder messages 
             -- distinct is optional, but 
             -- if you were to remove the "no event" condition, 
             -- multiple events could multiply the message count.
;

Answer 4

此查询使用联接来链接3个表，使用where子句和Group by筛选结果，并将结果限制为仅满足小于计数条件的对象。

SELECT    a.id, 
      SUM(CASE WHEN b.type = 'collection' THEN 1 ELSE 0 END),
      SUM(CASE WHEN c.type = 'collection_reminder' THEN 1 ELSE 0 END
FROM      users a 
left join   events b on (b.user_id = a.id)
left join   messages c on (c.user_id = a.id)
WHERE     a.admin = false
GROUP BY  a.id
HAVING  SUM(CASE WHEN b.type = 'collection' THEN 1 ELSE 0 END) = 0 
    AND SUM(CASE WHEN c.type = 'collection_reminder' THEN 1 ELSE 0 END) < 3

根据特定条件连接3个表

4 个答案: