Question

我正在使用PHP遍历书籍列表，并创建一个表单以将它们添加到具有不同状态（1 =已读，2 =正在阅读，3 =待读）的自己的列表中。

每本书都有一个唯一的ID。所以我最终使用foreach循环得到了这样的数组

foreach($_POST as $key => $val){
  $count++;
  $formElements[] = $val; 
}

Array ( [0] => 6748 [1] => 1 [2] => 6759 [3] => 2 [4] => 87804 [5] => 3 [6] => [7] => submit )

因此[0]和[1]是book_ID和状态。与[2]和[3]，[4]和[5]相同。

如何将它们合并在一起或将它们插入SQL表中？

显示我的表格，对不起！

<table>
          <thead>
            <tr><th></th>
            <th>Title</th>
            <th>Author</th>
          </tr></thead><tbody><tr>
            <td><input type="checkbox" value="6748" id="bookID" name="bookID1"></td>
            <td>A Supposedly Fun Thing I'll Never Do Again:  Essays and Arguments</td>
            <td>David Foster Wallace</td>
            <td><select name="readStatus1">
              <option></option>
              <option value="1">Read</option>
              <option value="2">Reading</option>
              <option value="3">To-Read</option>
            </select></td>

          </tr><tr>
            <td><input type="checkbox" value="6759" id="bookID" name="bookID2"></td>
            <td>Infinite Jest</td>
            <td>David Foster Wallace</td>
            <td><select name="readStatus2">
              <option></option>
              <option value="1">Read</option>
              <option value="2">Reading</option>
              <option value="3">To-Read</option>
            </select></td>

          </tr><tr>
            <td><input type="checkbox" value="87804" id="bookID" name="bookID3"></td>
            <td>Yes Man</td>
            <td>Danny Wallace</td>
            <td><select name="readStatus3">
              <option></option>
              <option value="1">Read</option>
              <option value="2">Reading</option>
              <option value="3">To-Read</option>
            </select></td>

          </tr><tr>
            <td><input type="checkbox" value="5986375" id="bookID" name="bookID4"></td>
            <td>This Is Water: Some Thoughts, Delivered on a Significant Occasion, about Living a Compassionate Life</td>
            <td>David Foster Wallace</td>
            <td><select name="readStatus4">
              <option></option>
              <option value="1">Read</option>
              <option value="2">Reading</option>
              <option value="3">To-Read</option>
            </select></td>

          </tr></tbody></table><input type="submit" value="submit" name="submit">

Answer 1

我建议您在表单内执行以下操作：

<input type="text" name="bookReadStatus[bookIDHERE]">
<input type="text" name="bookReadStatus[bookIDHERE]">

然后使用这种超级简单的方法将其导入数据库的方法就是

https://www.php.net/manual/en/function.implode.php

implode(',',$_POST);

Answer 2

以表格形式进行操作或转换为具有键值的数组

Array ( [0] => 6748 [1] => 1 [2] => 6759 [3] => 2 [4] => 87804 [5] => 3 [6] => [7] => submit )

// you could use foreach( $a as $v)
$ma = [
   [
       'id' => $a[0],
       'status' => $a[1]
   ],
   /* etc */

]

// use json_encode - use you pdo syntax here
'insert into mysql( "store field") values( "' + json_encode( $ma) +'")';

Answer 3

我的建议是使books数组已经存在于html中：

                                                         <!-- here -->
<td><input type="checkbox" value="6748" id="bookID" name="bookID[]"></td>
<td>A Supposedly Fun Thing I'll Never Do Again:  Essays and Arguments</td>
<td>David Foster Wallace</td>
                <!-- and here: -->
<td><select name="readStatus[]">
          <option></option>
          <option value="1">Read</option>
          <option value="2">Reading</option>
          <option value="3">To-Read</option>
</select></td>
<!-- repeat for other books coming from db -->

然后，您可以访问这些数组并在php中进行迭代：

foreach($_POST['bookID'] as $index => $id) {
     // use the bookID's index to get the status:
     $status = $_POST['readStatus'][$index];
     // now use $id and $status to insert into database.
     // either directly here in the loop, or build a new dedicated array:
     $books[] = ["id" => $id, "status" => $status];
     // and use that later to do your inserts.
}

或者，您也可以通过将ID用作索引来使用@TimHinz方法

合并两个数组值以使用SQL进行插入

3 个答案: