Question

"Roles":
{ 
    "0_A":["Developer"],
    "0_B":["Developer"],
    "0_C":["Developer","Tester","Player"],
    "0_D":["Tester"]
}

有没有办法检查'Roles'对象中是否存在值'Player'/'Tester'/'Developer'？这是我尝试过的：

let isPlayer= false;
if (response) {
  const k = Object.keys(response["Roles"]);
  for (let index = 0; index < k.length; index++) {
    if (response["Roles"][k[index]].indexOf("Player") > -1) {
      isPlayer= true;
      break;
    }
  }    
}

有没有没有for循环的方法？

谢谢！

Answer 1

如何如下使用.find()和.includes：

RethinkDB.uuid()

Answer 2

一种替代方法是在输入对象的Array.some()上将Array.includes()与Object.Values()结合使用。以下代码段显示了如何执行此操作的示例：

const response = {};
response["Roles"] = {
  "0_A":["Developer"],
  "0_B":["Developer"],
  "0_C":["Developer","Tester","Player"],
  "0_D":["Tester"]
};

const checkForType = (resp, type) =>
{
    let typeExists = false;

    if (resp)
    {
        let roles = resp["Roles"] || {};
        typeExists = Object.values(roles).some(arr => arr.includes(type));
    }

    return typeExists;
}

console.log(checkForType(response, "Player"));
console.log(checkForType(response, "Developer"));
console.log(checkForType(response, "Team Leader"));

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.as-console-wrapper {max-height:100% !important; top:0;}

Answer 3

您可以flatten Object.values()返回的2D数组，然后使用includes检查该数组是否包含角色名称：

const response = {
  "Roles": {
    "0_A": ["Developer"],
    "0_B": ["Developer"],
    "0_C": ["Developer", "Tester", "Player"],
    "0_D": ["Tester"]
  }
}

let isPlayer = Object.values(response.Roles)
                      .flat()
                      .includes("Player")
                      
console.log(isPlayer)

检查没有for循环的对象数组中是否存在值

3 个答案: