Question

我有一个JSON文件，其中包含我需要过滤的数据。

json是这个示例结构：

[{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData"},
{A:"data", C:"flightData", D:"FlightData"},
{B:"data", D:"FlightData"}]

我正在按方法分组

 function groupBy(list, keyGetter) {
        const map = new Map();
        list.forEach((item) => {
            const key = keyGetter(item);
            const collection = map.get(key);
            if (!collection) {
                map.set(key, [item]);
            } else {
                collection.push(item);
            }
        });
        return map;
    }

首先，我按A或B分组为数组

A is [[C],[D]]和B is[[C],[D]]

但是，如果数据中没有C或D，则由于不需要数据，我需要删除该组。

 for (let value of s1) {

           // A or B
          const routeGrouped = groupBy(PriceArrayFinal, route =>
                   route.FinalArrival);



            for (let origin of s3) {

          // C or D 
         const originGrouped = groupBy(routeGrouped.get(value), route =>

                     route.FirstDepartCityName);

如果C或D不存在，是否可以删除整个组，例如A：[ [C], [] ]。如果有一个空数组，我需要删除A或B组吗？

编辑：预期输出：A或B的所有组都具有C和D


[{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"}] 

 [ [ [Array], [Array] ], [ [Array], [Array] ] ,[ [Array], [Array] ], [ [Array], [Array] ] ]

Answer 1

如果要获取所有具有C && D值的对象，则可以像这样使用filter：

let input=[{A:"data",C:"flightData",D:"FlightData"},{B:"data",C:"flightData",D:"FlightData"},{A:"data",C:"flightData",D:"FlightData"},{B:"data",C:"flightData"},{A:"data",C:"flightData",D:"FlightData"},{B:"data",D:"FlightData"}];

let output = input.filter(({ C, D }) => C && D);

console.log(output)

Answer 2

使用数组filter()方法。

const arr = [{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData"},
{A:"data", C:"flightData", D:"FlightData"},
{B:"data", D:"FlightData"}];

const result = arr.filter(a => { 
 return (a.hasOwnProperty('A') || a.hasOwnProperty('B') && a.hasOwnProperty('C') && a.hasOwnProperty('D'));
});


console.log(result);
/* Expected Output:
[{A:"data", C:"flightData", D:"FlightData"},
{B:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"},
{A:"data", C:"flightData", D:"FlightData"}] 
*/

过滤数据-如何在JavaScript中过滤不需要的数据

2 个答案: