Question

我正在用Python 3教我的学生一些简单的代码，并且我们使用if / elif / else语句以及用户输入来编写简单的“选择自己的冒险”故事。我第一次编写此代码，它按预期运行。现在，无论输入了什么，它始终提供第一个选项。谁能解释为什么？谢谢！感谢大家！我的问题已解决。

cave=input('Would you like to enter the cave? Answer Y or N')

if cave == ('Y') or ('y'):
    print('The cave is cold.')
elif cave == ('N') or ('n'):
    print('Stay in the sunshine. Safe, but boring.')
else:
    print('That was not one of the choices.') 

tool= input ("You have two items in your bag: a torch and a sandwich. 
Which would you like to use?")
if tool == ("torch"):
    print ("The fire ignites the deadly gas that has built up in the 
cave. You die.")
elif tool ==("sandwich"):
    print ("Good idea. You'll need strength to explore the cave.")
else:
    print ("Why do you insist on making things difficult?")

Answer 1

此语句的计算是对还是错

if cave == ('Y') or ('y'):

应该是

if cave == ('Y') or cave == ('y'):

Answer 2

在Python中，没有“多重方程式检查”。当您要创建它时，您应该使用类似以下的内容：

if a == b or a == c:
    #some code here...

您还可以在中使用：

if a in (b, c):
    #some code here...

或

if a in [b, c]:
    #more code...

（这有点慢，所以在游戏中，我推荐第一个）

用户输入代码返回错误的响应

2 个答案: