我正在处理一个复选框表,提交的数据应保存在mysql数据库中。该表中有两列,自动递增ID,另一列用于保存复选框的值。
当前,即使我选择多个,一次也只保存一个值,只有最新的一个被保存。 这是代码:
report.php
<?php
$active = "report";
require_once 'pages/header.php';
require_once './functions/schema-functions.php';
$course = Schema::getCourse();
$objective = Schema::getObjective();
?>
<form id="addReport" action ='./functions/report-functions.php' method="post">
<table id="table1" class="table">
<?php
echo '<tr><th>Objectives</th>';
for ($i = 0; $i < count($course); $i++) {
echo '<th id = "rotate1">'. $course[$i]->commonName . '</th>';
}
echo '</tr>';
for ($y = 0; $y < count($objective); $y++) {
echo '<tr><th class=row-header>'.$objective[$y]->objective.'</th>';
for ($x = 0; $x < count($course); $x++) {
echo "<td><input name='check[]' type=checkbox value=c".$course[$x]->courseId."-o".$objective[$y]->objectiveId." id=checked></td>";
}
echo '</tr>';
}
?>
</table>
<input type="submit" name= "submit" value= "Submit"/>
report-functions.php
<?php
require_once 'db-connect.php';
if(isset($_POST['submit'])){
{
$conn = DatabaseConnection::getConnection();
$conn->beginTransaction();
if(isset($_POST['check'])){
foreach($_POST['check'] as $value){
$sql = $conn->prepare("INSERT INTO Report (ColRow) VALUES
('$value')");
}
if ($sql->execute(array( ':checked' => $checked))) {
$conn->commit();
return true;
} else {
$conn->rollback();
return false;
}
}
}
}
?>
我想在数据库的不同行中保存多个选中的复选框,提交后,我想再次显示该表并选中该复选框,用户应该能够进行检查并再次提交数据。
答案 0 :(得分:1)
要保存记录,您可以这样尝试:
<?php
if( isset( $_POST['submit'], $_POST['check'] ) ){
try{
require_once 'db-connect.php';
$conn = DatabaseConnection::getConnection();
$sql='insert into `report` ( `colrow` ) values ( :value )';
$stmt = $conn->prepare( $sql );
if( $stmt ){
$conn->beginTransaction();
foreach( $_POST['check'] as $index => $value ) {
$result = $stmt->execute( [ ':value' => $value ] );
if( !$result ) {
throw new Exception( sprintf( 'Failed to execute query %d for %s', $index, $value ) );
}
}
$conn->commit();
exit();
}
}catch( Exception $e ){
$conn->rollback();
exit( $e->getMessage() );
}
}
?>