I have a randomly generated custom number plate format which is as follows:
ISSIIIISS - Where 'I' is an Integer of 0-9 and 'S' is a string of A-Z
An example plate would be: 4DE2947BN
I am trying to find a way in which to calculate the total number of all possible combinations of this number plate format.
How can I do this and how could I use PHP or JavaScript to solve this problem?
I have some grasp of how you can calculate combinations but I am struggling on how this can be implemented into code, especially with the alphanumeric format that I am trying to calculate.
答案 0 :(得分:0)
I
being a number, there is 10 possibilities.
S
being a character, there is 26 possibilities.
The total number of combinations is 10 power (TheNumberOfI) * 26 power (TheNumberOfS)
This can be dynamically solved using a simple function that counts the number of S
and the number of I
and uses the results in the previous equation
function getNumberOfCombinations(input)
{
const countI = (input.match(/I/g) || []).length;
const countS = (input.match(/S/g) || []).length;
const result = Math.pow(10, countI) * Math.pow(26, countS);
return (result);
}
console.log(getNumberOfCombinations("ISSIIIISS"));
答案 1 :(得分:0)
I think it should become clear if you take it a piece at a time.
For the first "I", there are 10 possibilities, and for the first "S", there are 26,
so for those two characters together, the total number of possibilities is 10 x 26 = 260
.
Then for the next "S", you have 26 possibilities, so the first three characters together have 10 x 26 x 26 = 6760
possibilities.
The pattern continues until you get 26^4 * 10^5 = 45,697,600,000
, which in JS is
26**4 * 10**4
or
let x = Math.pow(26,4) * Math.pow(10,5);
console.log(x);