Question

对于如何直接从父类的__init__函数继承变量，我有些困惑。例如，我有以下内容：

class BaselineModels:
    def __init__(self):
        self.logpath = './log/models/'
        self.mpath = './models/'

然后，我创建一个具有自己的__init__并调用super()的子类，但是我似乎无法访问self.mpath。我知道与self绑定到类实例有关，但是由于我有很多子类不想复制这些路径变量，因此我将如何实现此功能。 / p>

我想要这样做的原因是，我从子类中调用了父类的函数，该子类使用父类的self变量（csv_to_df是父类的成员）：

def csv_to_df(self) -> tuple:
        """Reads in CSV file declared in __init__ (self.rpath) and converts it to a number of Pandas DataFrames.

        Returns:
            tuple: Returns tuple of Pandas DataFrames; user features, item features and 
                interactions between items.

        """

        df = pd.read_csv(self.rpath, sep='\t')
        return df

从子类中调用它会导致

Traceback (most recent call last):
  File "model_baselines.py", line 480, in <module>
    als.run()
  File "model_baselines.py", line 366, in run
    df = self.csv_to_df()
  File "model_baselines.py", line 46, in csv_to_df
    df = pd.read_csv(self.rpath, sep='\t')
AttributeError: 'ALS' object has no attribute 'rpath'

子类定义

class ALS(BaselineModels):
    def __init__(self):
        super()
        self.model_name = 'als'

    def run(self):
        df = self.csv_to_df()

我从文件底部调用als.run()。

编辑：已更新为包含子类定义

Answer 1

您必须调用__init__()对象的super()方法。像这样：

class BaselineModels:
    def __init__(self):
        self.logpath = './log/models/'
        self.mpath = './models/'

class ALS(BaselineModels):
    def __init__(self):
        super().__init__()
        self.model_name = 'als'

    def run(self):
        df = self.csv_to_df()


als = ALS()
als.mpath
# returns:
'./models/'

Answer 2

您也可以遵循此方法。

class BaselineModels:
    def __init__(self):
        self.logpath = './log/models/'
        self.mpath = './models/'

class ALS(BaselineModels):
    def __init__(self):
        super(ALS, self).__init__()
        self.model_name = 'als'

    def run(self):
        df = self.csv_to_df()


als = ALS()
als.mpath
# returns:
'./models/'

从父类（Python）继承变量的子类

2 个答案: