我想知道是否有人可以在这里提供帮助。我是Entity Framwork的新手。我有2个不同的Query.I想要加入它们并获得1.这是我的代码:
public static List<BankDepositHistory> GetAllByPagination(int page ,int stepes)
{
page=page-1;
using(MyketAdsEntities context = new MyketAdsEntities())
{
var transactionlist = context.BankDepositHistories.ToList();
var start = page * stepes;
var result= context.BankDepositHistories.OrderByDescending(c=>c.AccountId)
//anny code that give me count as field
.Skip(start)
.Take(stepes)
.ToList();
return (result);
}
}
public static int GetCount()
{
using (MyketAdsEntities context = new MyketAdsEntities())
{
int count = context.BankDepositHistories.Count();
return count;
}
}
如您所见,我有2种方法。我只想拥有GetAllByPagination。 非常感谢
答案 0 :(得分:1)
假设您在Entity下面,那么下面的设置应该可以使用。
public BankDepositHistory
{
public string UserName {get;set}
//etc..
}
创建视图模型
public class BankDepositHistoryVM
{
public List<BankDepositHistory> bankDetails {get;set;}
public int Count {get;set;}
}
返回视图模型
public static List<BankDepositHistoryVM> GetAllByPagination(int page ,int stepes)
{
page=page-1;
using(MyketAdsEntities context = new MyketAdsEntities())
{
var transactionlist = context.BankDepositHistories.ToList();
var start = page * stepes;
var result= context.BankDepositHistories.OrderByDescending(c=>c.AccountId)
.Skip(start)
.Take(stepes)
.ToList();
List<BankDepositHistoryVM> resultVM = new List<BankDepositHistoryVM>();
resultVM.bankDetails = result;
resultVM.Count = result.Count();
return resultVM;
}
}
调用方法:
List<BankDepositHistory> bankDetails = className.GetAllByPagination.bankDetails;
int count = className.GetAllByPagination.Count;
List<BankDepositHistoryVM> allDetails = className.GetAllByPagination();
希望有帮助。