Question

我在一张桌子的招待所中有5个房间，用户必须检查他们想要预订的一个或多个房间，并选择他们希望拥有的选项，例如人数，早餐选项，晚餐选项和床选项。

假设我们按出现顺序将这5个房间称为：

元素室

地球室

水室

飞机室

消防室

如果我按从上到下的顺序选择房间（例如元素到火的房间），则会得到结果选项，但是如果我选择两者之间的任何房间，则得到0。当从复选框中选中房间名称时，它的名称总是正确显示，但是选项值显示为0（第一个房间（元素）除外）

HTML：

<form class="booking-form" name="book-room-form" action="" id="contactForm" method="post" novalidate>

<?php foreach ( $rooms as $room ) : ?>

<input type="checkbox" class="form-check-input" name="room-selected[]" value="<?php echo $room->post_title; ?>">

<select class="num-person select-update" id="<?php echo 'r-' . $room->ID; ?>" name="people-select[]" required>
  <option value="0" selected>Select Number of Persons</option>
  <option value="1">1 person R600</option>
  <option value="2">2 persons R800</option>
</select>

<select class="num-dinner select-update" id="<?php echo 'd-' . $room->ID; ?>" name="dinner-select[]">
    <option value="0" selected>Select Dinner Course</option>
    <option value="120">Two Course Dinner R120</option>
    <option value="200">Three Course Dinner R200</option>
</select>

<select class="num-bf select-update" id="<?php echo 'b-' . $room->ID; ?>" name="breakfast-select[]">
    <option value="0" selected>Select Breakfast Type</option>
    <option value="70">Basic Breakfast R70</option>
    <option value="120">Full Breakfast R120</option>
</select>

<select class="bed-select" name="bed-select[]">
    <option selected>Select Bed Size</option>
    <option value="King Bed">King Bed</option>
    <option value="2 Single Beds">2 Single Beds</option>
</select>



<?php endforeach; ?>

    <button name="submit-request" type="submit" class="btn btn-primary">Submit</button>
</form>

代码：

if(isset($_POST['submit-request'])) {

    $room_selected = $_POST['room-selected'];
    $numPeople = $_POST['people-select'];
    $dinnerSelect = $_POST['dinner-select'];
    $breakfastSelect = $_POST['breakfast-select'];
    $bedSelect = $_POST['bed-select'];

    $room = $room_selected;
    $num = $numPeople;
    $dinn = $dinnerSelect;
    $bf  = $breakfastSelect;
    $bed = $bedSelect;

    foreach ($room as $id => $key) {
    //$key returns the room name
      if($key) {
        $result[$key] = array(
            'num_person'  => $num[$id],
            'dinner' => $dinn[$id],
            'breakfast'    => $bf[$id],
            'bed_type' => $bed[$id],
        );
    }

    echo $key . '<br/>' . $num[$id] . '<br/>' . $dinn[$id] . '<br/>' . $bf[$id] . '<br/>' . $bed[$id] . '<br/>' ;

    }

}

我希望能够选择任何房间并显示选项值

Answer 1

我之所以这样说是因为您没有在html表单数组中使用任何键。当前的解决方案有些脆弱，因此您需要在字段命名中更加具体，或者将键包含在数组中。

<?php foreach ( $rooms as $room ) : ?>

<input type="checkbox" class="form-check-input" name="room-selected[]" value="<?php echo $room->post_title; ?>">

<select class="num-person select-update" id="<?php echo 'r-' . $room->ID; ?>" name="people-select[<?php echo $room->post_title; ?>]" required>
  <option value="0" selected>Select Number of Persons</option>
  <option value="1">1 person R600</option>
  <option value="2">2 persons R800</option>
</select>

<select class="num-dinner select-update" id="<?php echo 'd-' . $room->ID; ?>" name="dinner-select[<?php echo $room->post_title; ?>]">
    <option value="0" selected>Select Dinner Course</option>
    <option value="120">Two Course Dinner R120</option>
    <option value="200">Three Course Dinner R200</option>
</select>

<select class="num-bf select-update" id="<?php echo 'b-' . $room->ID; ?>" name="breakfast-select[<?php echo $room->post_title; ?>]">
    <option value="0" selected>Select Breakfast Type</option>
    <option value="70">Basic Breakfast R70</option>
    <option value="120">Full Breakfast R120</option>
</select>

<select class="bed-select" name="bed-select[<?php echo $room->post_title; ?>]">
    <option selected>Select Bed Size</option>
    <option value="King Bed">King Bed</option>
    <option value="2 Single Beds">2 Single Beds</option>
</select>

<?php endforeach; ?>

然后，在运行循环而不是检查$ id时，请使用$ key。

if(isset($_POST['submit-request'])) {

    $room_selected = $_POST['room-selected'];
    $numPeople = $_POST['people-select'];
    $dinnerSelect = $_POST['dinner-select'];
    $breakfastSelect = $_POST['breakfast-select'];
    $bedSelect = $_POST['bed-select'];

    $room = $room_selected;
    $num = $numPeople;
    $dinn = $dinnerSelect;
    $bf  = $breakfastSelect;
    $bed = $bedSelect;

    foreach ($room as $id => $key) {
    //$key returns the room name
      if($key) {
        $result[$key] = array(
            'num_person'  => $num[$key],
            'dinner' => $dinn[$key],
            'breakfast'    => $bf[$key],
            'bed_type' => $bed[$key],
        );
    }

    echo $key . '<br/>' . $num[$key] . '<br/>' . $dinn[$key] . '<br/>' . $bf[$key] . '<br/>' . $bed[$key] . '<br/>' ;

    }

}

PHP发布如何在foreach循环中获取选项的值以显示所选值

1 个答案: