我想从冬眠的实体的日期列中获取年份

Question

 @ManyToMany(fetch = FetchType.LAZY)
        @JoinTable(name = "schedule_assignees",
                joinColumns = @JoinColumn(name = "schedule_id", referencedColumnName = "id"),
                inverseJoinColumns = @JoinColumn(name = "person_id", referencedColumnName = "id"))
        private List<Person> assignedTo;

服务方法：

 @Override
        public List<Integer> getScheduleYearsBy(Employee employee, Company company) {
            Person person = personRepository.findByIdAndCompany(employee.getId(),company);
            return scheduleRepository.findYearsBy(Arrays.asList(person), company);
        }

存储库方法

 @Query(value = "select distinct EXTRACT(YEAR FROM s.date) from Schedule s where (s.assignedTo in ?1)  " +
        "and (s.company = ?2) and s.archived=false")
List<Integer> findYearsBy(List<Person> person, Company company);

此存储库方法在eclipse链接中工作正常。但是在休眠状态时，其异常情况如下

 org.springframework.dao.InvalidDataAccessApiUsageException: Parameter value [com.orsbv.hcs.model.Employee@6a5] did not match expected type [java.util.Collection (n/a)]; nested exception is java.lang.IllegalArgumentException: Parameter value [com.orsbv.hcs.model.Employee@6a5] did not match expected type [java.util.Collection (n/a)]
        at org.springframework.orm.jpa.EntityManagerFactoryUtils.convertJpaAccessExceptionIfPossible(EntityManagerFactoryUtils.java:368)

有人可以建议使其在休眠状态下工作的方法吗？

Answer 1

最终更改存储库方法并使用QueryDSL并断言解决此问题

 @Override
    public List<Integer> findYearsBy(Person employee, Company company) {

        BooleanBuilder predicate = new BooleanBuilder();
        predicate.and(QSchedule.schedule.company.eq(company));
        predicate.and(QSchedule.schedule.archived.eq(Boolean.FALSE));
        predicate.and(QSchedule.schedule.assignedTo.any().eq(employee));

        return getQuerydsl()
                .createQuery()
                .from(QSchedule.schedule)
                .where(predicate)
                .select(QSchedule.schedule.date.year())
                .distinct()
                .fetch();
    }