我正在做我的第一个里程碑项目，如果满足获胜条件，我将无法使函数返回True。如果在板上连续3次看到“ X”或“ O”标记（井字棋），则函数应返回True。谁能澄清为什么它不返回True或False？
我首先将代码写为
return (board[7] == mark and board[8] == mark and board[9] == mark)
，但不会返回True。因此，我尝试对所有可能的获胜结果使用if和else语句，但我仍然无法使它返回True。只有当我用打印替换了return时，它才起作用。该函数接受两个参数，Board和Mark。
委员会是一个列表，出于测试目的，我使用了test_board = ['#','X','O','X','O','X','O','X','O','X']
我正在使用Visual Studio代码和终端来运行我的代码。
def win_check(board, mark):
return ((board[7] == mark and board[8] == mark and board[9] == mark) or # across top
(board[4] == mark and board[5] == mark and board[6] == mark) or # across middle
(board[1] == mark and board[2] == mark and board[3] == mark) or # across bottom
(board[7] == mark and board[4] == mark and board[1] == mark) or # down left
(board[8] == mark and board[5] == mark and board[2] == mark) or # down middle
(board[9] == mark and board[6] == mark and board[3] == mark) or # down right
(board[7] == mark and board[5] == mark and board[3] == mark) or # diagonal
(board[9] == mark and board[5] == mark and board[1] == mark)) # diagonal
然后我尝试使用if和else语句：
def win_check(board, mark):
if (board[7] == mark and board[8] == mark and board[9] == mark):
return True # across the top
elif(board[4] == mark and board[5] == mark and board[6] == mark):
return True # across the middle
elif(board[1] == mark and board[2] == mark and board[3] == mark):
return True # across the bottom
elif(board[7] == mark and board[4] == mark and board[1] == mark):
return True # down the middle
elif(board[8] == mark and board[5] == mark and board[2] == mark):
return True # down the middle
elif(board[9] == mark and board[6] == mark and board[3] == mark):
return True # down the right side
elif(board[7] == mark and board[5] == mark and board[3] == mark):
return True # diagonal
elif(board[9] == mark and board[5] == mark and board[1] == mark):
return True # diagonal
else :
return False
如果获胜条件为True，我希望输出为True