如何在Delphi中将LPARAM转换为结构？

Question

我需要帮助将LPARAM类型转换为结构。例如，在C ++中，我们有：

struct MyStructure
{
   int data01;
   int data02;
};

BOOL CALLBACK CallbackProc(int number, LPARAM param)
{
   MyStructure *myStruct = (MyStructure *) param;
}

在Delphi中，我尝试了此操作，但是编译器在突出显示的行上用注释给出了不兼容类型的错误：

type
  TMyStructure = record
    data01: Integer;
    data02: Integer;
  end;

PMyStructure = ^TMyStructure;

function CallbackProc(number: Integer; param: LPARAM): BOOL; stdcall;
var
  myStruct: TMyStructure;
begin
  myStruct := param; // How stays here?
end;

Answer 1

C ++代码将LPARAM强制转换为 pointer 的结构。在Delphi中，看起来像这样：

type
  TMyStructure = record
    data01: Integer;
    data02: Integer;
  end;
  PMyStructure = ^TMyStructure;

function CallbackProc(number: Integer; param: LPARAM): BOOL; stdcall;
var
  myStruct: PMyStructure;
begin
  myStruct := PMyStructure(param);
end;