Question

我如何检查列表中的值是整数还是字符串，并且如果它的整数是True

list = ["1 asd","sw asdd34","2asdas"]

如何检查该值是否以整数开头并返回True或False。

我尝试过：

        for i in range(1, len(array)):

        print("".join(array[i][:2]))
        try:
            if (int("".join(array[i][:4])) % 2 != 0):
                top_row.insert(i,array[i])
                print("port {} have been added on 
        top_row".format(array[i]))
            elif (int("".join(array[i][:4])) % 2 == 0):
                down_row.insert(i,array[i])
                print("port {} have been added on 
           down_row".format(array[i]))
            elif (int("".join(array[i][:4])) is not 
         (isinstance("".join(array[i][:4]), int))):
                top_row.insert(i,"NONE")
                print("add a none ")


            else:
                down_row.append(None)

Answer 1

一个相当不错的Python语言而且实际上非常快的方法就是尝试。

a = someintorstring

try:
    int(a)
    # it's an int
except ValueError:
    # not an int
    pass

Answer 2

它需要以整数开头吗？尝试正则表达式：

import re

for elem in your_list:
    if re.match(r'^[0-9]+', elem):
        # element starts with an integer, do your thing

如何检查值是整数还是字符串

2 个答案: