我知道Lisp中的subseq通过范围返回一个子序列。除了该范围,还有什么东西可以返回子序列,并且应该是非破坏性的吗?任何帮助表示赞赏。
答案 0 :(得分:2)
您可以使用concatenate
和subseq
对任何序列进行此操作:
(defun sequence-except (sequence start end)
(concatenate (sequence-type sequence)
(subseq sequence 0 start)
(subseq sequence end)))
以下内容足以确定位向量,字符串等的输入序列类型:
(defun sequence-type (sequence)
(etypecase sequence
(list 'list)
(array `(array ,(array-element-type sequence) (*)))))
测试:
(loop for test in (list
#*10101001
"abcd"
'(0 3 2)
nil
#(1 2 3 4)
(make-array 4
:adjustable t
:fill-pointer T
:initial-contents
'(a b c d)))
collect (concatenate (sequence-type test) test))
答案 1 :(得分:0)
你不能只是:
(defun seq-drop-subseq (SEQ START &optional END)
(if END
(nconc (seq-take START) (seq-drop END))
(seq-take START)))
编辑:不得不去看看。 remove
做到了。