Python迭代混乱

时间:2019-04-06 22:58:07

标签: python

正如您在下面看到的那样,我正在尝试制作一个程序,该程序接收一个名为names.txt的文件,并使用.split('/ n')将其分解为一个列表,然后为列表中的每个用户添加一个密码。由于某种原因,for外观将列表视为字符串,因此不要将其视为:

鲍勃 查理 罗恩

它像下面这样分解:

B Ø b

C H .... 因此,给每个字母一个密码而不是列表本身。

我在做什么错? 有没有一种方法可以测试以查看实际上给出了for循环?

我一直在使用它来查看是否给了它一个字符串,但是在打印时该列表似乎只是一个列表,所以为什么在for循环中将其视为字符串?

def importNames():

    try:
        file = open("names.txt", "r")
        contents = file.read()
        print(contents)
        file.close()

        return contents

    except:
        print("The file was not found.")
        print("Make sure you have a file called \"names.txt\" in the working directory (where you ran this program)")

        exit()

def createPasswordList(nameList):
    print("They are being given the standard password of \"p@ssw0rd.\"")
    #nameList = ["Pickles", "Bob's", 'wow zers john'] #This is for testing purposes. It works just fine, but the original nameList breaks down badly. 
    passList = []

    #for x, value in enumerate(nameList):
    for i in nameList:
        print(i)
        passList.append("p@ssw0rd")

    print(passList)
    return passList

def createUsers(nameList, passwordList): #takes in a list of usernames, then adds creates them. 
    for i in nameList:
        print("This will do something soon.")
        #encPass = crypt.crypt(passwordList[i],"22") #22 is a salt number, use crypt per useradd manual
        #os.system("useradd -p " + encPass + " " + nameList[i]) #useradd -p encryptedpass username

def convertNamesToList(originalList):
    print("Converting names.") #Use newline as a delimiter
    newList = originalList.split('\n')
    print(newList)
    return newList

def convertNameToUsernames(originalNames):
    print("Creating usernames")

print("This program is used to make some users.")
print("If you import a file, have it in the working directory called \"names.txt\".")

print("Would you like to import names or add them manually? (n/m)")
answer = input()

if (answer is 'm' or answer is 'M'):
    createUser()
    print("The user gets created. Good job.")

else:
    originalNames = importNames() #this will return a string of the file.
    convertNamesToList(originalNames) #convert the string to sets of names. Use newlines as delimiters. 
    #convert the names to usernames

    print("Do the users have passwords? (y/n)")
    #answer = input()
    answer = 'n' ###FORCE###
    if (answer is 'n' or answer is 'N'):
        passwordList = createPasswordList(originalNames)


2 个答案:

答案 0 :(得分:2)

对于convertNamesToList的返回值,您永远不会做任何事情。您不会将其存储在任何地方。然后,您将originalNames(它是一个字符串(甚至在注释中指出))传递给createPasswordList

我认为您想要类似的东西

originalNames = importNames() #this will return a string of the file.
listOfNames = convertNamesToList(originalNames) #convert the string to sets of names. Use newlines as delimiters. 
#convert the names to usernames

print("Do the users have passwords? (y/n)")
#answer = input()
answer = 'n' ###FORCE###
if (answer is 'n' or answer is 'N'):
    passwordList = createPasswordList(listOfNames)

答案 1 :(得分:0)

看起来您的nameList实际上是一个字符串。假设您在names.txt文件的每一行都有一个名称,请尝试以下操作:

def importNames():
    try:
        file = open("names.txt", "r")
        contents=[]
        for line in file.read():
            contents.append(line)
        print(contents)
        file.close()
        return contents

那么您以后就不需要将其转换为列表。

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