Question

我正在尝试解析此LOCAL XMLhttprequest，我正在获取正确的响应文本并将其显示在safari中。当我使用JSON.parse（）作为响应文本的对象时，无论如何更改.txt文件，都会收到诸如“ unidentified token'””或“ expected'}'“之类的错误，它将不会解析为对象对我来说

我尝试将.txt更改为正确的JSON格式

{playerGrid: [["3","2","2","2","2","2","2","3","3","3"], ["3","2","2","2","2","2","2","2","2","2"], ["3","2","2","2","2","2","2","2","2","3"],["3","2","2","2","2","2","2","2","2","3"], ["4","2","2","2","2","3","2","2","2","3"], ["2","2","2","2","7","3","2","2","2","3"], ["2","2","2","2","7","2","2","2","2","2"], ["2","2","2","3","3","3","2","2","2","2"], ["2","2","2,"2","2","2","2","2","2","2"], ["2","2","2","2","2","2","2","2","2","2"]],
computerGrid: [["2","2","2","7","4","9","9","2","2","2"], ["2","9","2","2","2","2","2","2","2","2"], ["2","9","2","2","2","2","2","2","2","2"], ["2","9","2","2","9","9","2","2,"2","2"], ["2","2","2","2","2","2","2","2","2","2"], ["9","9","9","9","9","2","2","2","2","2"], ["2","2","2","2","7","2","2","2","9","2"], ["2","2","2","2","2","2","2","2","9","2"], ["2","2","2","2","2","2","2","2","9","2"], ["2","2","2","2","2","2","2","2","9","2"]]};

这是我的JOSN .txt

function fileRequest()
{

  var localRequest = new XMLHttpRequest();

  localRequest.open("GET", "sampleJSON.txt", false);

  localRequest.send(null);

  document.getElementById("jsonDiv").innerHTML = localRequest.responseText;

  var jsonObject = JSON.parse(localRequest.response);

  document.getElementById("jsonParsed").innerHTML = jsonObject.computerGrid;

}

这是我的简单函数，首先显示响应，然后在尝试解析数据时出错。谢谢

我希望我可以使用.computerGrid或.playerGrid的对象。

Answer 1

您的json中有一些错误，只需按"2,进行搜索，就会发生2次，应该为"2",。
您缺少结束语"。

此外，为了使JSON有效，它应如下所示：

{"playerGrid":[["3","2","2","2","2","2","2","3","3","3"],["3","2","2","2","2","2","2","2","2","2"],["3","2","2","2","2","2","2","2","2","3"],["3","2","2","2","2","2","2","2","2","3"],["4","2","2","2","2","3","2","2","2","3"],["2","2","2","2","7","3","2","2","2","3"],["2","2","2","2","7","2","2","2","2","2"],["2","2","2","3","3","3","2","2","2","2"],["2","2","2","2","2","2","2","2","2","2"],["2","2","2","2","2","2","2","2","2","2"]],"computerGrid":[["2","2","2","7","4","9","9","2","2","2"],["2","9","2","2","2","2","2","2","2","2"],["2","9","2","2","2","2","2","2","2","2"],["2","9","2","2","9","9","2","2","2","2"],["2","2","2","2","2","2","2","2","2","2"],["9","9","9","9","9","2","2","2","2","2"],["2","2","2","2","7","2","2","2","9","2"],["2","2","2","2","2","2","2","2","9","2"],["2","2","2","2","2","2","2","2","9","2"],["2","2","2","2","2","2","2","2","9","2"]]}

键playerGrid和computerGrid必须在"之间。

Answer 2

使用JSON.parse(localRequest.responseText)
您的JSON不正确，您缺少诸如"2,
对象键"playerGrid"和"computerGrid"也必须加引号

let d = `{
"playerGrid": [
  ["3","2","2","2","2","2","2","3","3","3"], ["3","2","2","2","2","2","2","2","2","2"],
  ["3","2","2","2","2","2","2","2","2","3"], ["3","2","2","2","2","2","2","2","2","3"],
  ["4","2","2","2","2","3","2","2","2","3"], ["2","2","2","2","7","3","2","2","2","3"],
  ["2","2","2","2","7","2","2","2","2","2"], ["2","2","2","3","3","3","2","2","2","2"],
  ["2","2","2","2","2","2","2","2","2","2"], ["2","2","2","2","2","2","2","2","2","2"]],
"computerGrid": [
  ["2","2","2","7","4","9","9","2","2","2"], ["2","9","2","2","2","2","2","2","2","2"],
  ["2","9","2","2","2","2","2","2","2","2"], ["2","9","2","2","9","9","2","2","2","2"],
  ["2","2","2","2","2","2","2","2","2","2"], ["9","9","9","9","9","2","2","2","2","2"],
  ["2","2","2","2","7","2","2","2","9","2"], ["2","2","2","2","2","2","2","2","9","2"],
  ["2","2","2","2","2","2","2","2","9","2"], ["2","2","2","2","2","2","2","2","9","2"]]
}`;

console.log(JSON.parse(d))

PS：您始终可以使用codebeautify.org/jsonvalidator

来验证json。

JSON解析不起作用，解析二维数组

2 个答案: