我必须在OneToMany冲突模型中进行建模，并且我已经执行了ORM查询以将结果嵌套在这样的嵌套结构中：$u->userGroups()->with('space')->get()，并且得到了以下结果：
Illuminate\Database\Eloquent\Collection {#3158
all: [
App\UserGroup {#3142
role: "CONTRIBUTORS",
updated_at: "2019-04-06 16:38:43",
name: "Contributeurs",
created_at: "2019-04-06 16:38:43",
slug: "contributeurs",
id: 789,
space: App\Space {#3180
country: "Congo-Kinshasa",
address: "40 rue Zozo",
visibility: "public",
town: "Kinshasa",
updated_at: "2019-04-06 16:38:42",
name: "Christian Lisangola",
logo: "spaces/48fcacca888f0b35235b9edda371554dcfc2afc0.png",
created_at: "2019-04-06 16:38:42",
zip_code: "5767",
slug: "christian-lisangola",
id: 850,
},
},
App\UserGroup {#3145
role: "AUTHORS",
updated_at: "2019-04-06 16:38:43",
name: "Auteurs",
created_at: "2019-04-06 16:38:43",
slug: "auteurs",
id: 788,
space: App\Space {#3185
country: "Congo-Kinshasa",
address: "40 rue Luiss",
visibility: "public",
town: "Kinshasa",
updated_at: "2019-04-06 16:38:42",
name: "Christian Lisangola",
logo: "spaces/48fcacca888f0b35235b9edda371554dcfc2afc0.png",
created_at: "2019-04-06 16:38:42",
zip_code: "5767",
slug: "christian-lisangola",
id: 850,
},
},
App\UserGroup {#3148
role: "ADMINISTRATORS",
updated_at: "2019-04-06 16:37:37",
name: "Administrateurs",
created_at: "2019-04-06 16:37:37",
slug: "administrateurs",
id: 848,
space: App\Space {#3170
country: "États-Unis",
address: "100 avenue zazi",
town: "Houston",
visibility: "on_demand",
updated_at: "2019-04-06 16:37:37",
name: "US",
logo: "spaces/8490c3a93d32951d3d8d0ade7c459c70b202c342.png",
created_at: "2019-04-06 16:37:37",
zip_code: "33234",
slug: "us",
id: 766,
},
},
App\UserGroup {#3151
role: "ADMINISTRATORS",
updated_at: "2019-04-06 16:37:11",
name: "Administrateurs",
created_at: "2019-04-06 16:37:11",
slug: "administrateurs",
id: 765,
space: App\Space {#3175
country: "États-Unis",
address: "100 avenue zozo",
town: "Houston",
visibility: "private",
updated_at: "2019-04-06 16:37:11",
name: "Lims INC",
logo: "spaces/4f1c5ac285bbc38919133b83de58ac1f7802fea4.png",
created_at: "2019-04-06 16:37:11",
type: "private",
zip_code: "343",
slug: "lims-inc",
id: 844,
},
},
App\UserGroup {#3154
role: "ADMINISTRATORS",
updated_at: "2019-04-06 16:36:33",
name: "Administrateurs",
created_at: "2019-04-06 16:36:33",
slug: "administrateurs",
id: 1,
space: App\Space {#3165
country: "États-Unis",
address: "100 avenue zozo",
visibility: "public",
town: "Houston",
updated_at: "2019-04-06 16:36:33",
name: "Gravity",
logo: "spaces/4dab5e2bf8d8725b05186b9d574f8c98640526d9.png",
created_at: "2019-04-06 16:36:33",
zip_code: "111",
slug: "gravity",
id: 0,
},
},
],
我想要一种结构，其中我有一个成对键值数组，其格式为：["space.id"=>"role"]，如果对于给定的space.id，它们的键是重复的，它应该创建一个像这个['space.id'=>[role1,role2]]。为了解决这个问题，我在Laravel集合上使用了pluck方法。但是有两个主要问题。
上一个数组的结果保存在$result变量中。在该变量上，我这样调用了pluck方法：$result->pluck('role','space.id')->all()然后我得到了：
[
850 => "AUTHORS",
766 => "ADMINISTRATORS",
844 => "ADMINISTRATORS",
0 => "ADMINISTRATORS",
]
首先，当我进行修补时，一切都很好。但是，当我将结果以json格式发送给front-end时，space.id不会出现，这就是ajax call之后的样子：
[
"0" => "AUTHORS",
"1" => "ADMINISTRATORS",
"2" => "ADMINISTRATORS",
"3" => "ADMINISTRATORS",
]
所以，我不知道为什么原来的space.id不存在。
第二个问题：如果您仔细查看第一个数组space.id 850，它对CONTRIBUTORS和AUTHORS都重复了两次，因此它不支持duplicate keys和它为相同的key 850取了最新的值。但是我想为重复的键提供类似的东西：
[
850 => ["CONTRIBUTORS","AUTHORS"],//Take the 2 instead of only keep the latest value
766 => "ADMINISTRATORS",
844 => "ADMINISTRATORS",
0 => "ADMINISTRATORS",
]
但是我没有任何解决方案。谢谢
答案 0 :(得分：0)
我的答案将取决于Laravel集合，但您可以对其进行调整以在查询级别过滤结果（因为这样会更快），但是对于少量数据集，可以用php处理它们就足够了。
请注意，JSON不允许数组键具有不连续的整数键，因此每个[id => roles[]]映射都将成为一个对象，而您的输出将是：
{
"850": ["CONTRIBUTORS","AUTHORS"],
"766": ["ADMINISTRATORS"],
"844": ["ADMINISTRATORS"],
"0": ["ADMINISTRATORS"]
}
要将查询结果转换为json输出，您必须像这样处理它：
// Query the database
$groups = $u->userGroups()->with('space')->get();
$roles = $groups->groupBy(function ($group) {
// Group each 'UserGroup' by space.id
return $group->space->id;
})->map(function ($group) {
// For each group created, pluck the roles
return $group->pluck('role');
});
dd($roles->toJson());
注意：如果您的范围是将数据作为json返回给调用者，则还可以决定使用return response()->json($roles)而不是将其转换为json并打印为字符串。 / p>