Question

我尝试创建此更新语句，将今天的平均运行时间添加到临时表中。我一直收到以下语法错误：

错误：错误：语法错误在或附近   “内部”职位：22

查询   = UPDATE temptbl1 AS T INNER JOIN（选择jobno，avg（elaptime）as avgrun   来自cmr_runinf在哪里   TO_TIMESTAMP（TIMESTMP，   'YYYYMMDDHH24MISS'）＆gt; （现在（） -   间隔'1天'）GROUP BY JOBNO）AS   源ON T.jobno = source.jobno SET   T.todayrun   = source.avgrun

我的陈述：

UPDATE temptbl1 AS T
INNER JOIN
(
select jobno, avg(elaptime) as avgrun
from cmr_runinf
where to_timestamp(timestmp, 'YYYYMMDDHH24MISS') > (now() - interval '1 DAY')
GROUP BY JOBNO
) AS source
ON T.jobno = source.jobno
SET T.todayrun = source.avgrun

Answer 1

SET子句应该在UPDATE子句之后。你也可能想在某处有一个FROM子句。

UPDATE temptbl1 AS T1 
SET T1.todayrun = source.avgrun 
FROM ( 
    SELECT jobno, avg(elaptime) as avgrun 
      FROM cmr_runinf 
     WHERE to_timestamp(timestmp, 'YYYYMMDDHH24MISS') 
           > (now() - interval '1 DAY')
    GROUP BY jobno
) AS source
WHERE T1.jobno = source.jobno

另见http://www.postgresql.org/docs/current/interactive/sql-update.html

Answer 2

UPDATE temptbl1 AS T1 
SET T1.todayrun = source.avgrun 
FROM ( select jobno
            , avg(elaptime) as avgrun 
       from cmr_runinf 
       where to_timestamp(timestmp, 'YYYYMMDDHH24MISS')
                > (now() - interval '1 DAY')
       GROUP BY jobno     <-- not source.jobno, there is no source inside parenthesis
     ) AS source
WHERE T1.jobno = source.jobno

Answer 3

你拥有它的方式，它试图在虚拟表（两个物理表的连接）上执行更新，这是不允许的。

SET需要在更新后进行

postgresql语法错误

3 个答案: