如何在tkinter中制作9 x 9的按钮网格？

Question

对于一款游戏，我需要用tkinter制作9 x 9的按钮网格。任何想法如何做到这一点？ 并且如果按钮可以从1到9中随机选择数字，也将不胜感激。

这与另一个相同，但是我不明白如何使用他们正在使用的东西（例如类）以及如何更改网格以使其为9 x 9。

我试图为此创建一个for循环，但这是行不通的：

import tkinter

row = 1
column = 1
button = ["1","2","3","4","5","6","7","8","9"]

for x in button:
    button = tkinter.Button(bg="black", activebackground="white",width=2)
    button.grid(row=row, column=column)
    column = column + 1
    if column == "9": 
        row = row + 1
        column = 1
    else:
        column = column + 1

谢谢

Answer 1

我不确定，但我认为您需要3x3的内部9个按钮，所以我为3x3编写了代码。

我使用两个for循环来做到这一点。而it可以从清单中获取价值。更容易。

我使用random.shuffle来获取具有随机顺序的元素的列表。

请勿将Button关联到您已用于保存列表的变量button。

import tkinter as tk
import random

button = ["1","2","3","4","5","6","7","8","9"]
random.shuffle(button)

root = tk.Tk()

i = 0
for x in range(3):
    for y in range(3):
        number = button[i]
        btn = tk.Button(text=number, bg="black", activebackground="white", width=2)
        btn.grid(row=y, column=x)
        i += 1

root.mainloop()

编辑：我也可以使用inter()和next()代替i

import tkinter as tk
import random

button = ["1","2","3","4","5","6","7","8","9"]
random.shuffle(button)

root = tk.Tk()

it = iter(button)
for x in range(3):
    for y in range(3):
        number = next(it)
        btn = tk.Button(text=number, bg="black", activebackground="white", width=2)
        btn.grid(row=y, column=x)

root.mainloop()