我正在尝试在Julia中物理打开文件(不是读取数据,而是在Windows中打开文件)。
我尝试使用run(`test.txt`)
,但找不到文件。然后我意识到我需要一个命令在前面,所以我尝试了run(`run test.txt`)
。这似乎找到了文件,但是文件在启动时立即崩溃。我应该如何打开该文件?谢谢。
答案 0 :(得分:0)
虽然您不清楚“打开文件” 的概念,但是我认为您想在外部编辑器中查看文件。这将在Windows上运行:
using Microsoft.CodeAnalysis;
using Microsoft.CodeAnalysis.CSharp;
using Microsoft.CodeAnalysis.CSharp.Syntax;
using System;
using System.Linq;
namespace Tools.Tester
{
class Stackoverflow
{
public static void Question()
{
SyntaxTree tree = SyntaxFactory.ParseSyntaxTree(
@"
public class Class
{
public void Method(){}
}
"
);
//REPLACE CLASS
SyntaxNode Class = tree.GetRoot().DescendantNodes().OfType<ClassDeclarationSyntax>().First();
SyntaxNode ClassNew = Class.WithLeadingTrivia(SyntaxFactory.ParseLeadingTrivia("///<summery>XML</summery>").Add(SyntaxFactory.EndOfLine("\n")));
/*CLASS SHOULD NOW:
///<summery>XML</summery>
public class Class
{
public void Method(){}
}
*/
//REPLACE METHOD CHANGE TO CLASS NEW HERE
SyntaxNode Method = ClassNew.DescendantNodes().OfType<MethodDeclarationSyntax>().First();
SyntaxNode MethodNew = Method.WithLeadingTrivia(SyntaxFactory.ParseLeadingTrivia("///<summery>XML</summery>").Add(SyntaxFactory.EndOfLine("\n")));
/*METHOD SHOULD NOW:
///<summery>XML</summery>
public void Method(){}
*/
ClassNew = ClassNew.ReplaceNode(Method, MethodNew);
/*CLASS SHOULD NOW:
///<summery>XML</summery>
public class Class
{
///<summery>XML</summery>
public void Method(){}
}
*/
//UPDATE TREE
SyntaxTree treeNew = SyntaxFactory.ParseSyntaxTree(tree.GetRoot().ReplaceNode(Class, ClassNew).GetText());
string code = treeNew.GetText().ToString();
Console.WriteLine(code);
/*RESULT:
///<summery>XML</summery>
public class Class
{
public void Method(){}
}
*/
}
}
}