Question

以下内容（在调用core.js, maps.js, animated.js和上下文countryLow.js文件的情况下，将地图绘制成具有区域（或子行政区）的多边形：

var chart = am4core.create("chartdiv", am4maps.MapChart);
chart.geodata = am4geodata_franceLow;
chart.projection = new am4maps.projections.Miller();

var polygonSeries = chart.series.push(new am4maps.MapPolygonSeries());
polygonSeries.useGeodata = true;
polygonSeries.applyOnClones = true;
polygonSeries.fill = am4core.color("#a791b4");
polygonSeries.fillOpacity = 0.8; 
polygonSeries.strokeOpacity = 0.3;

var regionTemplate = polygonSeries.mapPolygons.template;
regionTemplate.tooltipText = "{name}";
regionTemplate.properties.fillOpacity = 0.8; 
regionTemplate.propertyFields.fill = "color";
regionTemplate.propertyFields.url = "url";
regionTemplate.columns.template.url = "http://localhost:3000/go/cities?region_id={properties.id()}"

显示工具提示时，如何在将多边形的ID值作为参数传递给URL的同时使该多边形可点击？

Answer 1

只需用Javascript而不是typescript编写零代码，就不会出现错误；

regionTemplate.url = "http://www.amcharts.com/";
regionTemplate.adapter.add("url", function(url, target) { return url + "?id=" + target.dataItem.dataContext.id; }):

Answer 2

您可以使用适配器修改原始网址，例如：

regionTemplate.url = "http://www.amcharts.com/";
regionTemplate.adapter.add("url", (url, target)=>{
   return url + "?id=" + target.dataItem.dataContext.id;
})

Answer 3

You can use placeholders in URLs.例如：

regionTemplate.url = "http://localhost:3000/go/cities?region_id={id.urlEncode()}"

演示：

https://codepen.io/team/amcharts/pen/30dc8cb2bcdef6a2d5f11d41db1e58a1

amcharts4使用面属性获取地图元素以链接到URL

3 个答案: