使用Moviepy Audiofile将mp4中的音频另存为wav文件

Question

我有一个名为'video.mp4'的视频文件。我正在尝试从视频中分离出一部分音频，并将其另存为可用于其他Python模块的wav文件。我想用MoviePy做到这一点。

我将参数发送到write_audiofile函数，并指定文件名，fps，nbyte和编解码器。

在MoviePy AudioClip docs之后，我将32位wav文件的编解码器指定为‘pcm_s32le’。

from moviepy.editor import *

sound = AudioFileClip("video.mp4")
newsound = sound.subclip("00:00:13","00:00:15")   #audio from 13 to 15 seconds
newsound.write_audiofile("sound.wav", 44100, 2, 2000,"pcm_s32le")

此代码生成一个名为.wav的{​​{1}}文件。

---

在Audacity中打开音频文件

生成的文件'sound.wav'可以在Audacity中打开，但是当我尝试将其与其他Python模块一起用作wav文件时遇到问题。

---

在pygame中播放声音文件

sound.wav

第三行给出以下错误：

import pygame pygame.mixer.init() sound=pygame.mixer.Sound("sound.wav")

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使用sndhdr.what（）确定声音文件的类型

pygame.error: Unable to open file 'sound.wav'

sndhdr方法返回了import sndhdr sndhdr.what("sound.wav") 。根据{{​​3}}，当发生这种情况时，该方法无法确定文件中存储的声音数据的类型。

---

通过Google语音识别读取文件

none

此代码在倒数第二行停止执行：

import speech_recognition as sr
r = sr.Recognizer()
audio = "sound.wav"

with sr.AudioFile(audio) as source:
    audio = r.record(source)
text= r.recognize_google(audio)
print(text)

---

如果ValueError: Audio file could not be read as PCM WAV, AIFF/AIFF-C, or Native FLAC; check if file is corrupted or in another format 无法将其识别为音频文件类型，为什么音频文件以Audacity打开？ 如何正确将MoviePy AudioClip导出为sndhdr.what()文件？

Answer 1

我有同样的问题。我试图从URL获取mp4文件，然后将其转换为wav文件，然后通过它调用Google语音识别。相反，我使用pydub来处理转换，并且有效！这是代码示例：

    import requests
    import io
    import speech_recognition as sr
    from pydub import AudioSegment


    # This function translate speech to text
    def speech_to_text(file):
        recognizer = sr.Recognizer()
        audio = sr.AudioFile(file)
        with audio as source:
            speech = recognizer.record(source)
            try:
                # Call recognizer with audio and language
                text = recognizer.recognize_google(speech, language='pt-BR')
                print("Você disse: " + text)
                return text
            # If recognizer don't understand
            except:
                print("Não entendi")

    def mp4_to_wav(file):
        audio = AudioSegment.from_file(file, format="mp4")
        audio.export("audio.wav", format="wav")
        return audio

    def mp4_to_wav_mem(file):
        audio = AudioSegment.from_file_using_temporary_files(file, 'mp4')
        file = io.BytesIO()
        file = audio.export(file, format="wav")
        file.seek(0)
        return file


    url = ''
    r = requests.get(url, stream=True)
    file = io.BytesIO(r.content)
    file = mp4_to_wav_mem(file)
    speech_to_text(file)

请注意，我编写了两个函数：mp4_to_wav和mp4_to_wav_mem。唯一的区别是mp4_to_wav_mem处理内存中的所有文件，而mp4_to_wav生成.wav文件。

Answer 2

我阅读了MoviePy的文档，发现参数nbyte应该与codec一致。 nbyte用于样本宽度（对于16位声音，设置为2，对于32位声音，设置为4）。因此，最好在设置nbyte=4时设置codec=pcm_s32le。

Answer 3

我在未指定编解码器或编解码器='pcms32le'的情况下遇到了相同的问题，对我有用的是 pcm_s16le 。 请注意，我使用的是“ fr-FR”语言，您可能应该适应您的需求。 这是完整的代码：

# Python code to convert video to audio
import moviepy.editor as mp
import speech_recognition as sr

# Insert Local Video File Path
clip = mp.VideoFileClip("/tmp/data/test.mp4")

# Insert Local Audio File Path
clip.audio.write_audiofile("/tmp/data/test.wav",codec='pcm_s16le')

# initialize the recognizer
r = sr.Recognizer()

# open the file
with sr.AudioFile("/tmp/data/test.wav") as source:
    # listen for the data (load audio to memory)
    audio_data = r.record(source)
    # recognize (convert from speech to text)
    text = r.recognize_google(audio_data, language = "fr-FR")
    print(text)

Answer 4

我认为这是正确的方法：

Type=c("A", "B", 1, "C", 2, 3, 4)
Description=c("","","DNA1", "", "DNA2", "DNA3", "DNA4")
Gene=c("","","rp1", "", "rp2","rp3", "rp4")

data=data.frame(Type, Description, Gene, stringsAsFactors = FALSE)

Answer 5

我认为这种方法很容易理解。

from moviepy.editor import *
input_file = "../Database/myvoice.mp4"
output_file = "../Database/myvoice.wav"
sound = AudioFileClip(input_file)
sound.write_audiofile(output_file, 44100, 2, 2000,"pcm_s32le")